The density of a certain liquid is \(1.15 \mathrm{~g} / \mathrm{mL}\). What mass in grams of the liquid is needed to fill a \(50.00\) -mL container? Do this problem by the method of algebraic manipulation, beginning with the equation density \(=\) mass/volume and showing all steps.

Short Answer

Expert verified
The mass of the liquid needed to fill the 50.00 mL container is \(57.50\mathrm{g}\).

Step by step solution

01

Write the equation for density

As we know, the formula for density is given by: density = mass/volume
02

Plug in the given values

We are given the values of density and volume. The density is 1.15 g/mL, and the volume is 50.00 mL. Now, plug these values into the density formula: \(1.15 \frac{\mathrm{g}}{\mathrm{mL}} = \frac{\mathrm{mass}}{50.00 \mathrm{mL}}\)
03

Solve for mass

To find the mass, we need to isolate the mass on one side of the equation. We will do this by multiplying both sides by the volume, which is 50.00 mL: \(1.15 \frac{\mathrm{g}}{\mathrm{mL}} * 50.00 \mathrm{mL} = \mathrm{mass}\)
04

Simplify the equation

Now, we can simplify the equation and remove any unnecessary units: \((1.15\mathrm{g}) * (50.00 /\cancel{\mathrm{mL}}) * (\cancel{\mathrm{mL}}) = \mathrm{mass}\)
05

Calculate the mass

Our equation is now in its simplest form, and we can simply multiply 1.15 g by 50.00 to find the mass. \((1.15\mathrm{g}) * (50.00) = 57.50\mathrm{g}\) So, the mass of the liquid needed to fill the 50.00 mL container is 57.50 grams.

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