Chapter 2: Problem 185
At \(25^{\circ} \mathrm{C}\), air has a density of \(1.3 \times 10^{-3} \mathrm{~g} / \mathrm{mL}\). What is this density in (a) kilograms per liter and (b) pounds per gallon?
Short Answer
Expert verified
(a) The density of air at $25^{\circ} \mathrm{C}$ in kilograms per liter is \(1.3 \: \text{kg/L}\).
(b) The density in pounds per gallon is approximately \(0.0108 \: \text{lb/gal}\).
Step by step solution
01
Convert grams to kilograms
First, let's convert the mass units from grams to kilograms. We know that 1 kg = 1,000 g.
So, we have:
Density = \[1.3 \times 10^{-3}\] g/mL
02
Convert density to kilograms per liter
Now that we have the mass units in kilograms, we need to convert the volume units from milliliters to liters. We know that 1 liter = 1,000 mL.
Hence, the density in kilograms per liter will be:
Density = \[1.3 \times 10^{-3}\] kg/L *(1,000 mL / 1 L)
03
Calculate the density in kilograms per liter
Now we can simply calculate the density:
Density = \[1.3 \times 10^{-3}\] kg/L * (1,000)
Density (kg/L) = 1.3
So, the density in kilograms per liter is 1.3 kg/L.
04
Convert grams to pounds
Next, we need to convert the mass unit from grams to pounds in order to find the density in pounds per gallon. We can use the conversion factor: 1 pound = 453.592 grams.
Density = \[1.3 \times 10^{-3}\] g/mL * (1 lb / 453.592 g)
05
Convert milliliters to gallons
In this step, we need to convert the volume units from milliliters to gallons. We can use the conversion factor: 1 gallon = 3,785.41 mL.
Density = (\[1.3 \times 10^{-3}\] lb / mL) * (1 gal / 3,785.41 mL)
06
Calculate the density in pounds per gallon
Now we can calculate the density in pounds per gallon:
Density = \[ {(1.3 \times 10^{-3}) \times (1 / 453.592)} \div (1 / 3,785.41) \] lb/gal
Density (lb/gal) ≈ 0.0108
Hence, the density in pounds per gallon is approximately 0.0108 lb/gal.
To summarize, the density of air at 25°C is:
(a) 1.3 kg/L
(b) 0.0108 lb/gal
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Mass Unit Conversion
Understanding mass unit conversion is fundamental in various fields, particularly in chemistry, where precise measurements are crucial. In our example, we needed to convert air's density from grams per milliliter to kilograms per liter and pounds per gallon. To break it down, the conversion process typically involves a basic multiplication or division by conversion factors. A conversion factor is a ratio equal to one that expresses the same quantity in different units.
For instance, since 1 kilogram equals 1,000 grams, converting grams to kilograms requires dividing the mass value by 1,000. Such conversions allow scientists and students to work with units that are more familiar or more convenient for a given situation. For practicing mass conversions, it's useful to have a list of common conversion factors at hand, such as:
For instance, since 1 kilogram equals 1,000 grams, converting grams to kilograms requires dividing the mass value by 1,000. Such conversions allow scientists and students to work with units that are more familiar or more convenient for a given situation. For practicing mass conversions, it's useful to have a list of common conversion factors at hand, such as:
- 1 kilogram = 1,000 grams
- 1 pound = 453.592 grams
Volume Unit Conversion
Volume unit conversion is just as important as mass unit conversion, especially in problems requiring density computations. Volume conversions often involve switching between milliliters and liters or between milliliters and gallons, as seen in our density conversion problem. Since density is mass per unit volume, it is important to use consistent volume units to prevent errors.
When converting volume units, remember that 1 liter is equivalent to 1,000 milliliters, and there are about 3,785.41 milliliters in a gallon. By applying the conversion factors, we can scale up or down between units:
When converting volume units, remember that 1 liter is equivalent to 1,000 milliliters, and there are about 3,785.41 milliliters in a gallon. By applying the conversion factors, we can scale up or down between units:
- To convert from milliliters to liters, divide by 1,000.
- To convert from milliliters to gallons, divide by 3,785.41.
Chemistry Problem Solving
Chemistry problem solving often involves a mix of conceptual knowledge and practical skill in applying concepts to real-world problems. It's a step-by-step process, starting with understanding the question, identifying the applicable concepts (like density in our case), and knowing which units need to be converted. After that, it’s a matter of executing the correct calculations, often using the dimensional analysis method.
In our exercise, the steps to convert units of density were systematically followed to ensure precision in the final result. When solving chemistry problems:
In our exercise, the steps to convert units of density were systematically followed to ensure precision in the final result. When solving chemistry problems:
- Always begin by identifying what you are given and what needs to be found.
- Write down all known conversion factors related to the units in the problem.
- Use dimensional analysis, also known as the unit factor method, to convert the units step by step, cancelling out units along the way.
- Finally, check your work to ensure the resulting units and magnitude make sense for the context.