Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 2: Problem 20

$$ 22.0 \text { miles } \times 2.0 \text { miles }=? $$

Short Answer

Expert verified
The short answer based on the step-by-step solution is: \(44.0 \, miles^2\).

Step by step solution

01

Analyze the given exercise

We are given two distances 22.0 miles and 2.0 miles, and we need to multiply them. Let's break down the problem into the multiplication of the numbers and taking care of the units.
02

Multiply the numbers

To multiply the given numbers, simply multiply their values: \( 22.0 \times 2.0 = 44.0 \)
03

Handle the units

Both numbers have the unit "miles" so when multiplying, we should multiply the units as well: \( miles \times miles = miles^2 \)
04

Combine the values and units

Finally, combine the values from Step 2 and the units from Step 3: \( 44.0 \, miles^2 \) So, the result of the multiplication is: \(22.0 \, miles \times 2.0 \, miles = 44.0 \, miles^2\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Using a ruler marked in centimeters and millimeters, a student measures the diameter of a ball to be \(1.5 \mathrm{~cm}\). His partner measures the same ball with the same ruler and comes up with \(1.50\) \(\mathrm{cm}\). Which student used the ruler incorrectly? How did that student use the ruler incorrectly?

Calculate the amount of heat energy in joules required to heat \(50.0 \mathrm{~g}\) of each substance from \(25.0^{\circ} \mathrm{C}\) to \(37.0^{\circ} \mathrm{C}\). (specific heats shown in parentheses): (a) Iron \(\left(0.449 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\right)\) (b) Aluminum (0.901 J/g \(\cdot{ }^{\circ} \mathrm{C}\) ) (c) Mercury \(\left(0.14 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\right)\) (d) Water \(\left(4.18 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\right)\)

Is reporting a measured mass as \(580 . \mathrm{g}\) the same as reporting it as \(580 \mathrm{~g}\) ? Explain.

Indicate whether the trailing zero in each value is significant, not significant, or possibly significant: (a) \(540 \pm 0.5\) (b) \(540 \pm 5\) (c) \(0.540\) (d) \(0.000540\) (e) 540

You overhear a classmate telling another student that \(1 \mathrm{ft}\) equals \(12 \pm 0.5 \mathrm{in}\). Is this statement correct or incorrect? Why?
See all solutions

Recommended explanations on Chemistry Textbooks

Inorganic Chemistry

Read Explanation

Kinetics

Read Explanation

Making Measurements

Read Explanation

Chemical Reactions

Read Explanation

Chemical Analysis

Read Explanation

Ionic and Molecular Compounds

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free