Chapter 2: Problem 25
\(1555 \mathrm{in} .+0.001 \mathrm{in} .+0.2 \mathrm{in}=?\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 2: Problem 25
\(1555 \mathrm{in} .+0.001 \mathrm{in} .+0.2 \mathrm{in}=?\)
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeThe density of a certain liquid is \(1.15 \mathrm{~g} / \mathrm{mL}\). What mass in grams of the liquid is needed to fill a \(50.00\) -mL container? Do this problem by the method of algebraic manipulation, beginning with the equation density \(=\) mass/volume and showing all steps.
Convert to cal \(/ \mathrm{g} \cdot{ }^{\circ} \mathrm{C}:\) (a) \(1.04 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\) (the specific heat of nitrogen gas) (b) \(0.84 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\) (the specific heat of carbon dioxide gas)
Using a bathroom scale, a tub, a sponge, and a measuring cup, explain how you would measure your own density.
Without doing any numerical calculations, determine which would have the smallest volume: (a) \(50 \mathrm{~g}\) of water (density \(=1.0 \mathrm{~g} / \mathrm{mL}\) ) (b) \(50 \mathrm{~g}\) of salt water (density \(=2.3 \mathrm{~g} / \mathrm{mL}\) ) (c) \(50 \mathrm{~g}\) of mercury (density \(=13.6 \mathrm{~g} / \mathrm{mL}\) ) (d) \(50 \mathrm{~g}\) of alcohol (density \(=0.89 \mathrm{~g} / \mathrm{mL}\) ) Explain your reasoning.
The density of an irregularly shaped object is determined by immersing the object in water. If the mass of the object is \(8.34 \mathrm{~g}\) and the water level rises from \(25.00 \mathrm{~mL}\) to \(28.10 \mathrm{~mL}\), what is the density of the object in grams per milliliter?
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