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Chapter 2: Problem 31

How many milliliters are there in \(1.000 \mathrm{~L}\) ?

Short Answer

Expert verified
There are \(1{,}000 \mathrm{~mL}\) in \(1.000 \mathrm{~L}\).

Step by step solution

01

Understand the conversion factor

1 liter (L) is equal to 1,000 milliliters (mL). So the conversion factor between liters and milliliters is: 1 L = 1,000 mL
02

Use the conversion factor to find the answer

Now we need to convert the given value 1.000 L to milliliters. To do this, we will multiply the given liters by the conversion factor (1 L = 1,000 mL). Calculation: \(1.000 \mathrm{~L} \times 1{,}000 \frac{\mathrm{mL}}{\mathrm{L}} = 1{,}000 \mathrm{~mL} \)
03

State the final answer

There are 1,000 milliliters (mL) in 1.000 liters (L).

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Most popular questions from this chapter

A metal sphere has a radius \(r\) of \(4.00 \mathrm{~cm}\). What is the volume \(V\) of this sphere in cubic centimeters? The formula for the volume of a sphere is \(V=(4 / 3) \pi r^{3}\), where \(\pi=3.14159 .\)

The density of water at \(4.00^{\circ} \mathrm{C}\) is \(1.00 \mathrm{~g} / \mathrm{mL}\). The density of ice at \(0{ }^{\circ} \mathrm{C}\) is \(0.917 \mathrm{~g} / \mathrm{mL}\). Water is different from most other substances in that the solid phase (ice) is less dense than the liquid phase. Explain why this characteristic makes ice fishing possible.

Use a scientific calculator to do the following calculations. Express each answer in scientific notation and to the correct number of significant figures. (a) \(9.865 \times 10^{3}+8.61 \times 10^{2}\) (b) \(\frac{\left(6.626 \times 10^{23}\right) \times\left(3.00 \times 10^{8}\right)}{4.5 \times 10^{-7}}\) (c) \(\frac{5.6200 \times 10^{-9}}{3.821 \times 10^{9}}\) (d) \(\frac{4.5600 \times 10^{3}-2.91 \times 10^{1}}{5}\), where the 5 is an exact number

Define density, and explain why the unit for density is called a derived SI unit.

(a) Solve the equation \(y=z / x\) for \(x\). (b) Solve the equation \(y=z / 2 x\) for \(x\).
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