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Chapter 2: Problem 47

Given \(p / q=r\), solve for \(p\).

Short Answer

Expert verified
The short answer to the given equation \( \frac{p}{q} = r \) is to multiply both sides by \(q\) to isolate \(p\), resulting in the solution: \( p = rq \).

Step by step solution

01

Write down the given equation

We start with the given equation: \( \frac{p}{q} = r \)
02

Isolate p

To isolate \(p\), we need to eliminate the fraction. Since \(p\) is divided by \(q\) in the fraction, to eliminate the denominator, we can multiply both sides of the equation by \(q\). This operation gives us: \( p = rq \)
03

Final answer

After isolating \(p\), the solution to the given equation \(p / q = r\), is: \[ p = rq \]

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Most popular questions from this chapter

Write each number in standard notation: (a) \(1.79 \times 10^{-2}\) (b) \(8.76 \times 10^{-9}\) (c) \(4.88 \times 10^{10}\) (d) \(7.52 \times 10^{1}\) (e) \(8.37 \times 10^{\circ}\) (f) \(4.184 \times 10^{4}\)

How much heat energy is 1 cal? Give your answer in terms of changing the temperature of water.

Convert: (a) \(2.37 \times 10^{2} \mathrm{~L}\) to milliliter (b) \(800 \mathrm{~kg}\) to grams (c) \(0.592 \mathrm{~mm}\) to meters (d) \(8.31 \mathrm{~g}\) to kilograms (e) \(9.62 \times 10^{-6} \mathrm{~L}\) to microliters (f) \(8000 \mathrm{~m}\) to kilometers (g) \(19.3 \mathrm{mg}\) to grams (h) \(0.00345 \mathrm{~mL}\) to liters

Do the following calculations and express each answer to the correct number of significant figures. (All values are measurements.) (a) \(\frac{5.03+7.2}{0.003}\) (b) \(\frac{8.93 \times 0.054}{1.32}\) (c) \((6.23 \times 0.042)+9.86\)

The specific heat of methane gas is \(2.20 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\). If the temperature of a sample of methane gas rises by \(15^{\circ} \mathrm{C}\) when \(8.8 \mathrm{~kJ}\) of heat energy is added to the sample, what is the mass of the sample?
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