A student makes a compound of sulfur and oxygen. She uses \(5.00 \mathrm{~g}\) of sulfur and \(4.99 \mathrm{~g}\) of oxygen, and all of the elemental substances are completely used up. What is the percent sulfur in the compound?

Short Answer

Expert verified
The percent of sulfur in the compound is approximately \(50.05\% \).

Step by step solution

01

Calculate the total mass of the compound

To find the total mass of the compound, we simply add the mass of sulfur used and the mass of oxygen used since both compounds are completely used up. Total mass = mass of sulfur + mass of oxygen
02

Plug in the given values

We have the mass of sulfur as \(5.00\text{ g}\) and the mass of oxygen as \(4.99\text{ g}\). Plugging these values into the equation from step 1: Total mass = \(5.00\text{ g} + 4.99\text{ g}\)
03

Calculate the total mass

Adding the masses of sulfur and oxygen, we get: Total mass = \(9.99\text{ g}\)
04

Calculate the percent of sulfur in the compound

Now that we have the total mass, we can calculate the percentage of sulfur in the compound: Percent sulfur = \(\frac{\text{mass of sulfur}}{\text{total mass}} \times 100\)
05

Plug in the values and calculate the percentage

Insert the values of mass of sulfur (5.00 g) and total mass (9.99 g) into the equation: Percent sulfur = \(\frac{5.00\text{ g}}{9.99\text{ g}} \times 100\)
06

Calculate and write the final answer

Complete the calculation: Percent sulfur = \(\frac{5.00}{9.99} \times 100 = 50.05 \% \) The percent of sulfur in the compound is approximately \(50.05\% \).

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