Two different compounds, both consisting of sodium (Na) and oxygen (O), were analyzed. The data are given below: $$ \begin{array}{cccc} & \begin{array}{l} \text { Mass of } \\ \text { sample } \\ \text { Compound } \end{array} & \begin{array}{l} \text { Mass of } \\ \text { analyzed } \end{array} & \text { O present } & \begin{array}{l} \text { Mass of } \\ \text { Na present } \end{array} \\ \hline \mathrm{A} & 19.50 \mathrm{~g} & 8.00 \mathrm{~g} & ? \\ \mathrm{~B} & 61.98 \mathrm{~g} & 16.00 \mathrm{~g} & ? \\ \hline \end{array} $$ (a) Fill in the last column of the table. (b) Calculate the \(\% \mathrm{Na}\) and \(\% \mathrm{O}\) for both compounds.

Short Answer

Expert verified
In conclusion, for compound A, the mass of Na is 11.50g, \%Na ≈ 58.97%, and \%O ≈ 41.03%. For compound B, the mass of Na is 45.98g, \%Na ≈ 74.18%, and \%O ≈ 25.82%.

Step by step solution

01

Calculate the mass of Na present in each compound

To find the mass of Na present in each compound, we can subtract the mass of O from the total mass of the sample. Use the following formula: Mass of Na = Mass of sample - Mass of O For compound A: Mass of Na = 19.50g - 8.00g Mass of Na = 11.50g For compound B: Mass of Na = 61.98g - 16.00g Mass of Na = 45.98g So, the mass of Na present in compound A is 11.50g, and in compound B is 45.98g.
02

Calculate the percentage of Na and O present in compound A

To find the percentage of an element in a compound, divide the mass of the element by the total mass of the compound and multiply by 100. Use the following formula: Percentage of element = (Mass of element / Mass of sample) * 100 For Na in compound A: % Na = (11.50g / 19.50g) * 100 % Na ≈ 58.97 % For O in compound A: % O = (8.00g / 19.50g) * 100 % O ≈ 41.03 % The percentage of Na in compound A is approximately 58.97%, and the percentage of O is approximately 41.03%.
03

Calculate the percentage of Na and O present in compound B

Using the same formula as in step 2, calculate the percentages for compound B: For Na in compound B: % Na = (45.98g / 61.98g) * 100 % Na ≈ 74.18 % For O in compound B: % O = (16.00g / 61.98g) * 100 % O ≈ 25.82 % The percentage of Na in compound B is approximately 74.18%, and the percentage of O is approximately 25.82%. In conclusion: - For compound A, the mass of Na is 11.50g, the percentage of Na is 58.97%, and the percentage of O is 41.03%. - For compound B, the mass of Na is 45.98g, the percentage of Na is 74.18%, and the percentage of O is 25.82%.

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