Name each element and tell how many valence electrons it has: (a) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{2}\) (b) \([\mathrm{Ne}] 3 \mathrm{~s}^{1}\) (c) \([\mathrm{Ar}] 4 s^{2} 3 d^{10} 4 p^{3}\)

Short Answer

Expert verified
(a) Silicon (Si) with 4 valence electrons. (b) Sodium (Na) with 1 valence electron. (c) Arsenic (As) with 5 valence electrons.

Step by step solution

01

(a) Identify the element and valence electrons for \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{2}\)

We can determine the total number of electrons by adding the superscript of all the terms: \(1s^{2}\) has 2 electrons \(2s^{2}\) has 2 electrons \(2p^{6}\) has 6 electrons \(3s^{2}\) has 2 electrons \(3p^{2}\) has 2 electrons Adding all electrons, we get: 2+2+6+2+2=14 electrons An element with 14 electrons is Silicon (Si). The valence electrons are the outermost electrons, present in the 3rd shell: \(3s^{2} 3p^{2}\). Thus, Silicon has a total of 4 valence electrons.
02

(b) Identify the element and valence electrons for \([\mathrm{Ne}] 3 \mathrm{~s}^{1}\)

This electron configuration begins with the noble gas Neon (Ne) and has an additional electron in the \(3s^{1}\) orbital. Neon has 10 electrons; therefore, this element has 11 electrons in total. An element with 11 electrons is Sodium (Na). Since the additional electron is in the 3rd shell, Sodium has 1 valence electron.
03

(c) Identify the element and valence electrons for \([\mathrm{Ar}] 4 s^{2} 3 d^{10} 4 p^{3}\)

This electron configuration stars with the noble gas Argon (Ar) and has additional electrons in the \(4s^{2}\), \(3d^{10}\), and \(4p^{3}\) orbitals. Argon has 18 electrons; therefore, with the additional electrons, this element has 18+2+10+3 = 33 electrons in total. An element with 33 electrons is Arsenic (As). The valence electrons are in the 4th shell: \(4s^{2} 4p^{3}\). Thus, Arsenic has a total of 5 valence electrons.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free