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Chapter 4: Problem 184

What is the highest value of \(n\) for the electrons in these atoms? (a) \(\overline{\mathrm{Co}}\) (b) As (c) \(\overline{\mathrm{Sr}}\) (d) \(\overline{\mathrm{Po}}\)

Short Answer

Expert verified
The highest values of the principal quantum number (n) for the given elements are: (a) Cobalt (Co): \(n = 4\) (b) Arsenic (As): \(n = 4\) (c) Strontium (Sr): \(n = 5\) (d) Polonium (Po): \(n = 6\)

Step by step solution

01

(a) Find the electron configuration for Co

Co is Cobalt and has an atomic number of 27. Using the periodic table, we can determine Co's electron configuration: \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^7\]
02

(a) Determine the highest value of n for Co

The electron configuration of Cobalt reveals that the period with the highest principal quantum number (n) is the 4th period: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^7\). Therefore, the highest value of n for Cobalt (Co) is 4.
03

(b) Find the electron configuration for As

As is Arsenic and has an atomic number of 33. Using the periodic table, we can determine As's electron configuration: \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^3\]
04

(b) Determine the highest value of n for As

The electron configuration of Arsenic reveals that the period with the highest principal quantum number (n) is the 4th period: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^3\). Therefore, the highest value of n for Arsenic (As) is 4.
05

(c) Find the electron configuration for Sr

Sr is Strontium and has an atomic number of 38. Using the periodic table, we can determine Sr's electron configuration: \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2\]
06

(c) Determine the highest value of n for Sr

The electron configuration of Strontium reveals that the period with the highest principal quantum number (n) is the 5th period: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2\). Therefore, the highest value of n for Strontium (Sr) is 5.
07

(d) Find the electron configuration for Po

Po is Polonium and has an atomic number of 84. Using the periodic table, we can determine Po's electron configuration: \[1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^{14} 5d^{10} 6p^4\]
08

(d) Determine the highest value of n for Po

The electron configuration of Polonium reveals that the period with the highest principal quantum number (n) is the 6th period: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^{14} 5d^{10} 6p^4\). Therefore, the highest value of n for Polonium (Po) is 6.

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Most popular questions from this chapter

Why is the formula for calcium sulfide \(\mathrm{CaS}\) and not \(\mathrm{Ca}_{2} \mathrm{~S} ?\)

Write electron configurations for \(\mathrm{O}, \mathrm{O}^{2+}\), and \(\mathrm{O}^{2-}\). Which form would you expect to find in most compounds of oxygen? Why?

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