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Chapter 5: Problem 26

Give the proper name for the compound \(\mathrm{TiCl}_{4}\).

Short Answer

Expert verified
Titanium(IV) chloride

Step by step solution

01

Identify the elements in the compound

The compound is made up of titanium (Ti) atoms and chlorine (Cl) atoms.
02

Determine the oxidation state of titanium

In \(\mathrm{TiCl}_{4}\), there are 4 chlorine atoms, each with an oxidation state of -1. Since the compound is neutral, the oxidation state of titanium must be +4 to balance the charges.
03

Use the systematic naming conventions

Titanium is a transition metal and can have multiple oxidation states, so we need to include its oxidation state in the name. Since the oxidation state of titanium is +4, we will use the Roman numeral IV as a suffix in parentheses after the metal name. The name of the compound is therefore Titanium(IV) chloride.

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Most popular questions from this chapter

The polyatomic ion \(\mathrm{MnO}_{4}^{2-}\) is listed in your book as permanganate. What would be the name of \(\mathrm{MnO}_{3}^{2-} ?\)

The molecule \(\mathrm{HCl}\) is known, but the molecule \(\mathrm{HeCl}\) is not. Explain why this is so.

Suppose one of the electrons from the covalent bond in \(\mathrm{H}_{2}\) suddenly vanished. Why would the bond between the atoms weaken?

Give the proper name for the following compounds: (a) \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) (b) \(\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}\) (c) \(\mathrm{KClO}\) (d) \(\mathrm{CaCO}_{3}\) (e) \(\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}\)

How many electrons does an atom gain for ea covalent bond that it forms in a molecule?
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