Consider \(\mathrm{SO}_{2}\) and \(\mathrm{CO}_{2}\). Both have polar covalent bonds. One of these molecules is polar and the other is nonpolar. Which is which and why?

Short Answer

Expert verified
\(\mathrm{SO}_{2}\) is a polar molecule because of its bent molecular geometry and the difference in electronegativity between sulfur and oxygen atoms. In contrast, \(\mathrm{CO}_{2}\) is nonpolar due to its linear molecular geometry and the cancellation of bond dipoles, despite the electronegativity difference between carbon and oxygen.

Step by step solution

01

Determine the electronegativity of the atoms in the molecules

: Electronegativity is the ability of an atom to attract the shared electrons in a bond. In both \(\mathrm{SO}_{2}\) and \(\mathrm{CO}_{2}\), there are polar covalent bonds. Oxygen has a higher electronegativity (3.44) than carbon (2.55) and sulfur (2.58), causing an uneven sharing of electrons between the atoms.
02

Analyze the molecular geometry of the molecules

: To determine the polarity of the entire molecule, we need to analyze the molecular geometry. A molecule's shape is based on the arrangement of its atoms, which can be predicted by the VSEPR (valence shell electron pair repulsion) theory. For \(\mathrm{SO}_{2}\), the central atom is sulfur, which has an expanded octet with six valence electrons, and there are two terminal oxygen atoms. The molecular geometry of \(\mathrm{SO}_{2}\) is a bent (angular) shape, with a bond angle of approximately 120 degrees. For \(\mathrm{CO}_{2}\), the central atom is carbon with four valence electrons, and there are two terminal oxygen atoms. The molecular geometry of \(\mathrm{CO}_{2}\) is linear, with a bond angle of 180 degrees.
03

Determine the polarity of the molecules based on electronegativity and molecular geometry

: Considering both electronegativity and molecular geometry, we can now determine the polarity of \(\mathrm{SO}_{2}\) and \(\mathrm{CO}_{2}\). In \(\mathrm{SO}_{2}\), the bent geometry combined with the different electronegativities of sulfur and oxygen atoms causes the individual bond dipoles to not cancel each other out, resulting in a net molecular dipole moment. Therefore, \(\mathrm{SO}_{2}\) is a polar molecule. In contrast, \(\mathrm{CO}_{2}\) has a linear geometry, and despite the difference in electronegativity between carbon and oxygen, the bond dipoles are exactly opposite, cancelling each other out. This results in no net molecular dipole moment. Therefore, \(\mathrm{CO}_{2}\) is a nonpolar molecule.
04

Conclusion

: \(\mathrm{SO}_{2}\) is a polar molecule due to its bent molecular geometry and the difference in electronegativity between sulfur and oxygen atoms, while \(\mathrm{CO}_{2}\) is a nonpolar molecule due to its linear molecular geometry and the cancellation of the bond dipoles, even with the electronegativity difference between carbon and oxygen.

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Most popular questions from this chapter

There are exceptions to the predictions of VSEPR. Consider \(\mathrm{CH}_{3}\), known as a methyl radical. (a) Create a dot diagram for the methyl radical. How is it fundamentally different from other dot diagrams you have done? (b) Use VSEPR to predict the shape of the methyl radical and draw it with that shape (treat the odd electron as a single electron group). (c) The methyl radical is known to be planar with \(120^{\circ} \mathrm{H}-\mathrm{C}-\mathrm{H}\) angles. What steric number is being employed here, and what is the carbon atom doing with respect to the odd electron in determining molecular shape? (d) The \(\mathrm{CF}_{3}\) radical does obey VSEPR. Draw it according to its VSEPR-predicted shape. What steric number is being employed here? (e) The \(\mathrm{C}-\mathrm{H}\) bond is shorter than the \(\mathrm{C}-\mathrm{F}\) bond. When bonds are short, the atoms at the ends of the bonds can bang into each other (this is called steric congestion) unless a geometry is adopted to get around this. Use this knowledge to explain why \(\mathrm{CH}_{3}\) violates VSEPR, but \(C F_{3}\) does not.

Consider the methane molecule. (a) Draw the methane molecule showing its tetrahedral shape, using lines, solid wedges, and dashed wedges to show three-dimensionality. (b) Draw the methane molecule inscribed inside ? tetrahedron such that the \(\mathrm{H}\) atoms touch the vertices of the tetrahedron. (c) Why is it better for methane to have \(109.5^{\circ}\) bond angles rather than \(90^{\circ}\) bond angles?

Consider the two molecules \(\mathrm{CO}\) and \(\mathrm{CO}_{2}\). They are both made of the same elements, and yet only one is polar. Why is this so?

Consider the molecule \(\mathrm{N}_{2} \mathrm{O}\) (connected \(\mathrm{N}-\mathrm{N}-\mathrm{O})\) (a) Draw the dot diagram. (b) Draw the molecule's three-dimensional shape, and label the numeric value of all bond angles. (c) What is the shape of this molecule? (d) Draw in the individual bond dipole moments. (e) Is the molecule polar? If yes, draw the molecular dipole moment vector.

The connections in \(\mathrm{CH}_{3} \mathrm{NO}_{2}\) are: (a) Put in the remaining valence electrons to complete the Lewis dot diagram. (b) Using lines, solid wedges, and dashed wedges, draw the three-dimensional shape of this molecule. Indicate the numeric value of all bond angles.

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