Using lines, solid wedges, and dashed wedges, draw the three-dimensional shape of chloromethylacetylene, \(\mathrm{C}_{3} \mathrm{H}_{3} \mathrm{Cl}\). Indicate the numeric value of all bond angles.

Short Answer

Expert verified
The three-dimensional structure of chloromethylacetylene (C3H3Cl) can be represented as: H 180° / C≡C-C-Cl 180° 180° The molecule has a linear arrangement with bond angles of 180° between H-C≡C, C≡C-C, and C-C-Cl.

Step by step solution

01

Draw the Central Carbon Atoms

First, draw a line to represent the triple bond between the two carbon atoms and a single bond connecting the central carbon atom (C) with the other carbon atom (C) in a linear arrangement: C≡C-C
02

Add the Hydrogen Atom

Now, let's add the hydrogen atom (H) connected to the first carbon atom by a single bond. Since this hydrogen bond would be coming out of the plane, we draw it using a solid wedge: H / C≡C-C
03

Add the Chlorine Atom

Next, draw the chlorine atom (Cl) bonded to the last carbon atom in linear arrangement by a single bond: H / C≡C-C-Cl
04

Indicate Bond Angles

Now, we will indicate the numeric values of the bond angles. In this molecule, there are three atoms involved: hydrogen (H), carbon (C), and chlorine (Cl). - The bond angle between H, the first C, and the second C is 180° because of the linear arrangement. - The bond angle between the first C, the second C (in the triple bond), and the third C is also 180° because of the linear connection. - The bond angle between the second C, the third C, and Cl is also 180°, again due to the linear arrangement. Add these angle values to the drawing: H 180° / C≡C-C-Cl 180° 180° The final representation of the chloromethylacetylene molecule (C3H3Cl) is as follows: H 180° / C≡C-C-Cl 180° 180°

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