\(\mathrm{HNO}_{3}\), in which hydrogen is attached to one of the oxygens and all oxygens are attached to nitrogen. To simplify, ignore the hydrogen when you name the molecule's shape.

In the given molecule, \(\mathrm{HNO}_{3}\), nitrogen (N) is the central atom. This is because nitrogen has a lower electronegativity compared to oxygen, and it is less likely to form multiple bonds with oxygen.

The next step is to calculate the total number of valence electrons. Nitrogen (N) has 5 valence electrons, and each oxygen (O) atom has 6 valence electrons. In this molecule, there are 3 oxygen atoms and 1 nitrogen atom. So, the total number of valence electrons is: \(5 + (3 \times 6) = 5 + 18 = 23\)

In the given molecule, \(\mathrm{HNO}_{3}\), there are three oxygen atoms connected to the central nitrogen atom. Since each bond requires 2 valence electrons, the total number of valence electrons used for bonding with oxygen atoms is 6 (3 bonds * 2 electrons per bond). Now, subtract the number of valence electrons used for bonding from the total valence electrons: \(23 - 6 = 17\) Since each lone electron pair consists of 2 electrons, there are 17 / 2 = 8.5 lone electron pairs. However, this is an odd number of electrons, which indicates the presence of an odd electron species, in this case, the hydrogen atom. To simplify the shape naming, ignore the hydrogen atom as mentioned in the exercise. Thus, we'll consider 8 lone electrons (4 lone electron pairs) and assign the extra electron to the hydrogen atom.

The central nitrogen atom has three bonding electron pairs with the oxygen atoms and four lone electron pairs. Therefore, the electron domain geometry around nitrogen is trigonal bipyramidal (five electron pairs). However, since we are considering only oxygen atoms for determining the molecule's shape and ignoring the hydrogen atom, we'll focus only on the three oxygen atoms bonded to nitrogen. In this case, the shape of the molecule, considering only the nitrogen and oxygen atoms, is trigonal planar, as the three oxygen atoms are placed around nitrogen at approximately 120° angles.