The following are solids at room temperature (about \(25^{\circ} \mathrm{C}\) ). Classify them as molecular, ionic, network, or metallic: (a) Zirconium, \(\mathrm{Zr}, \mathrm{mp}=1852{ }^{\circ} \mathrm{C}\) (b) Lead, \(\mathrm{Pb}, \mathrm{mp}=328^{\circ} \mathrm{C}\) (c) Calcium nitride, \(\mathrm{Ca}_{3} \mathrm{~N}_{2}, \mathrm{mp}=1195^{\circ} \mathrm{C}\) (d) Graphite form of carbon, \(\mathrm{C}\), sublimes at \(3652{ }^{\circ} \mathrm{C}\) (e) Yellow phosphorus, \(\mathrm{P}_{4}, \mathrm{mp}=44^{\circ} \mathrm{C}\)

Short Answer

Expert verified
(a) Zirconium (Zr) is a metallic solid. (b) Lead (Pb) is a metallic solid. (c) Calcium Nitride (Ca3N2) is an ionic solid. (d) Graphite form of carbon (C) is a network solid. (e) Yellow Phosphorus (P4) is a molecular solid.

Step by step solution

01

(a) Classify Zirconium (Zr)

Zirconium (Zr) is a metal, so it will have metallic bonding. Thus, Zirconium will be classified as a metallic solid.
02

(b) Classify Lead (Pb)

Lead (Pb) is also a metal and has metallic bonding. Therefore, Lead will be classified as a metallic solid.
03

(c) Classify Calcium Nitride (Ca3N2)

Calcium Nitride (Ca3N2) is a compound formed by a metal (Calcium) and a non-metal (Nitrogen). It has ionic bonding between the metal (positive ions) and non-metal (negative ions). So, Calcium Nitride will be classified as an ionic solid.
04

(d) Classify Graphite form of carbon (C)

Graphite is a form of carbon (C) which has covalent bonds (network covalent bonding) between the individual atoms, forming a vast network of interconnected carbon atoms. As a result, graphite will be classified as a network solid.
05

(e) Classify Yellow Phosphorus (P4)

Yellow Phosphorus (P4) is a covalent compound with molecular (covalent) bonding between the individual P4 molecules. Since it has molecular bonds and is not part of a larger network or ionic structure, Yellow Phosphorus will be classified as a molecular solid. To summarize: (a) Zirconium (Zr) is a metallic solid. (b) Lead (Pb) is a metallic solid. (c) Calcium Nitride (Ca3N2) is an ionic solid. (d) Graphite form of carbon (C) is a network solid. (e) Yellow Phosphorus (P4) is a molecular solid.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free