Predict which compound in each pair will have the higher melting point, and explain why for each pair. (a) HI or KI (b) \(\mathrm{Na}_{2} \mathrm{O}\) or \(\mathrm{H}_{2} \mathrm{O}\) (c) \(\mathrm{CaF}_{2}\) or \(\mathrm{HF}\) (d) \(\mathrm{SiO}_{2}\) or \(\mathrm{CO}_{2}\)

Short Answer

Expert verified
(a) KI will have a higher melting point than HI as ionic compounds have stronger electrostatic forces compared to covalent molecules. (b) \(\mathrm{Na}_{2} \mathrm{O}\) will have a higher melting point than \(\mathrm{H}_{2} \mathrm{O}\) because ionic compounds have stronger attractive forces compared to molecular compounds. (c) \(\mathrm{CaF}_{2}\) will have a higher melting point than \(\mathrm{HF}\) since the ionic bonds in \(\mathrm{CaF}_{2}\) are stronger than the hydrogen bonds in \(\mathrm{HF}\). (d) \(\mathrm{SiO}_{2}\) will have a higher melting point than \(\mathrm{CO}_{2}\) due to its giant covalent structure with strong covalent bonds, while \(\mathrm{CO}_{2}\) has weaker dispersion forces between its molecules.

Step by step solution

01

(a) Compare HI and KI

To compare HI (Hydrogen iodide) and KI (Potassium iodide), let's first identify the bonding types. HI is a covalent molecule, while KI is an ionic compound. Ionic compounds typically have stronger electrostatic forces between their positively and negatively charged ions, leading to higher melting points. Therefore, we can predict that KI will have a higher melting point than HI.
02

(b) Compare \(\mathrm{Na}_{2} \mathrm{O}\) and \(\mathrm{H}_{2} \mathrm{O}\)

Both \(\mathrm{Na}_{2} \mathrm{O}\) (Sodium oxide) and \(\mathrm{H}_{2} \mathrm{O}\) (Water) contain oxygen, but while \(\mathrm{Na}_{2} \mathrm{O}\) is an ionic compound, \(\mathrm{H}_{2} \mathrm{O}\) is a molecular compound. As previously explained, ionic compounds usually have stronger attractive forces, leading to higher melting points. Thus, we can predict that \(\mathrm{Na}_{2} \mathrm{O}\) will have a higher melting point than \(\mathrm{H}_{2} \mathrm{O}\).
03

(c) Compare \(\mathrm{CaF}_{2}\) and \(\mathrm{HF}\)

\(\mathrm{CaF}_{2}\) (Calcium fluoride) is an ionic compound, while \(\mathrm{HF}\) (Hydrogen fluoride) is a molecular compound with hydrogen bonding, which is a stronger type of intermolecular force. Despite that, the ionic bonds in \(\mathrm{CaF}_{2}\) are stronger than the hydrogen bonds in \(\mathrm{HF}\). Therefore, we can predict that \(\mathrm{CaF}_{2}\) will have a higher melting point than \(\mathrm{HF}\).
04

(d) Compare \(\mathrm{SiO}_{2}\) and \(\mathrm{CO}_{2}\)

Both \(\mathrm{SiO}_{2}\) (Silicon dioxide) and \(\mathrm{CO}_{2}\) (Carbon dioxide) are molecular compounds. \(\mathrm{SiO}_{2}\) forms a giant covalent structure, while \(\mathrm{CO}_{2}\) is a simple covalent molecule. The giant covalent structure of \(\mathrm{SiO}_{2}\) has very strong covalent bonds that require a large amount of energy to break. In contrast, the intermolecular forces between \(\mathrm{CO}_{2}\) molecules are weaker dispersion forces. As a result, we can predict that \(\mathrm{SiO}_{2}\) will have a higher melting point than \(\mathrm{CO}_{2}\).

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