Chapter 7: Problem 62
Which of the following would most likely be a gas at room temperature? Justify your choice. (a) \(\mathrm{NaCl}\) (b) \(\mathrm{C}_{2} \mathrm{H}_{2}\) (c) Na metal (d) \(\mathrm{CH}_{3} \mathrm{~F}\)
Chapter 7: Problem 62
Which of the following would most likely be a gas at room temperature? Justify your choice. (a) \(\mathrm{NaCl}\) (b) \(\mathrm{C}_{2} \mathrm{H}_{2}\) (c) Na metal (d) \(\mathrm{CH}_{3} \mathrm{~F}\)
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Get started for freeWhich of the following would you expect to have the highest boiling point? Justify your choice. (a) Propane, \(\mathrm{C}_{3} \mathrm{H}_{8}\) (b) Carbon dioxide, \(\mathrm{CO}_{2}\) (c) Ethyl alcohol, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) (d) Methyl fluoride, \(\mathrm{CH}_{3} \mathrm{~F}\)
On the molecular level, describe each phase of matter with respect to the amount of order present.
Both diamond and graphite are network solids consist solely of carbon atoms: In diamond, every carbon atom is bonded to four other carbon atoms. In graphite, every carbon atom is bonded to three other carbon atoms, creating sheets of atoms that lie on top of one another. (a) Which type of intermolecular forces exist between the sheets of carbon atoms in graphite? (b) Diamond is an extremely hard substance, whereas graphite is a soft, slippery substance often used as a lubricant. Use intramolecular and intermolecular forces to explain this difference in physical properties.
Consider the molecules HF and HCl. The electronegativities of the atoms involved are \(\mathrm{H}, 2.1 ; \mathrm{Cl}, 3.0 ; \mathrm{F}, 4.0 .\) (a) Which of the two molecules is more polar? Explain your answer. (b) For which substance are the dipole-dipole attractions between the molecules stronger? Explain your answer. (c) Which gas would, upon cooling, liquefy first? Explain your answer. Also, indicate which compound would have the higher boiling point based on your answer. (d) Do both molecules also experience London forces of attraction? If yes, which would have the greater London forces?
Why do we use dotted lines rather than solid lines to represent hydrogen bonds?
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