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Chapter 8: Problem 105

When propane gas, \(\mathrm{C}_{3} \mathrm{H}_{8}\), reacts with oxygen gas, carbon dioxide gas and water are produced. Write the balanced equation for the reaction.

Short Answer

Expert verified
The balanced chemical equation for the reaction of propane gas with oxygen gas is: \(C_{3}H_{8} + 7O_{2} \rightarrow 3CO_{2} + 4H_{2}O\).

Step by step solution

01

Write the unbalanced chemical equation

Write down the unbalanced chemical equation: \(C_{3}H_{8} + O_{2} \rightarrow CO_{2} + H_{2}O\)
02

Balance carbon atoms

There are 3 carbon atoms on the left side of the equation (in the propane molecule) and only 1 on the right side (in the CO2 molecule). Add a coefficient of 3 in front of CO2 to balance the carbon atoms: \(C_{3}H_{8} + O_{2} \rightarrow 3CO_{2} + H_{2}O\)
03

Balance hydrogen atoms

There are 8 hydrogen atoms on the left side of the equation (in the propane molecule) and only 2 on the right side (in the H2O molecule). Add a coefficient of 4 in front of H2O to balance the hydrogen atoms: \(C_{3}H_{8} + O_{2} \rightarrow 3CO_{2} + 4H_{2}O\)
04

Balance oxygen atoms

There are now 6 + 8 = 14 oxygen atoms on the right side of the equation. To balance the oxygen atoms, add a coefficient of 7 in front of O2 on the left side of the equation: \(C_{3}H_{8} + 7O_{2} \rightarrow 3CO_{2} + 4H_{2}O\) Now the chemical equation is balanced with the same number of atoms of each element on both sides of the equation. So, the balanced chemical equation for the reaction of propane gas with oxygen gas is: \(C_{3}H_{8} + 7O_{2} \rightarrow 3CO_{2} + 4H_{2}O\)

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