Chapter 8: Problem 113

A solution containing which anion can be added to separate: (a) \(\mathrm{Na}^{+}(a q)\) from \(\mathrm{Ag}^{+}(a q)\) (b) \(\mathrm{Na}^{+}(a q)\) from \(\mathrm{Ca}^{2+}(a q)\)

Short Answer

Expert verified

(a) A solution containing Cl- ions can be added to separate Na+\( (a q) \) from Ag+\( (a q) \). (b) A solution containing C2O4\( ^{2-} \) ions can be added to separate Na+\( (a q) \) from Ca2+\( (a q) \).

Step by step solution

The goal is to find an anion that will form a precipitate with Ag+ but not with Na+. To do this, we need to consider which anion will form an insoluble compound with Ag+, but still remain soluble with Na+. #Step 2: Choose suitable anion for separation of Na+ and Ag+

One such anion is the chloride ion (Cl-). According to solubility rules, silver chloride (AgCl) is an insoluble compound, while sodium chloride (NaCl) is soluble. Adding a solution containing the chloride ion (e.g., NaCl or HCl) to the mixture of Na+ and Ag+ ions will cause AgCl to precipitate, while Na+ will remain in the solution as NaCl. (a) A solution containing Cl- ions can be added to separate Na+(aq) from Ag+(aq). #Step 3: Identify possible anion for separation of Na+ and Ca2+ ions

The goal is to find an anion that will create a precipitate with Ca2+ but not with Na+. We need to consider which anion will form an insoluble compound with Ca2+, but remain soluble with Na+. #Step 4: Choose suitable anion for separation of Na+ and Ca2+

One such anion is the oxalate ion (C2O4^2-). According to solubility rules, calcium oxalate (CaC2O4) is an insoluble compound, whereas sodium oxalate (Na2C2O4) is soluble. By adding a solution containing the oxalate ion (e.g., Na2C2O4 or H2C2O4) to the mixture of Na+ and Ca2+ ions, CaC2O4 will precipitate, while Na+ will remain in the solution as Na2C2O4. (b) A solution containing C2O4^2- ions can be added to separate Na+(aq) from Ca2+(aq).

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A solution containing which anion can be added to separate: (a) \(\mathrm{Na}^{+}(a q)\) from \(\mathrm{Ag}^{+}(a q)\) (b) \(\mathrm{Na}^{+}(a q)\) from \(\mathrm{Ca}^{2+}(a q)\)

Short Answer

Step by step solution

The goal is to find an anion that will form a precipitate with Ag+ but not with Na+. To do this, we need to consider which anion will form an insoluble compound with Ag+, but still remain soluble with Na+. #Step 2: Choose suitable anion for separation of Na+ and Ag+

The goal is to find an anion that will create a precipitate with Ca2+ but not with Na+. We need to consider which anion will form an insoluble compound with Ca2+, but remain soluble with Na+. #Step 4: Choose suitable anion for separation of Na+ and Ca2+

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