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Chapter 8: Problem 124

Write the balanced equation for the reaction that occurs when an aqueous solution of carbonic acid, \(\mathrm{H}_{2} \mathrm{CO}_{3}\), is mixed with an aqueous solution of lithium hydroxide, \(\mathrm{LiOH}\).

Short Answer

Expert verified
The balanced chemical equation for the reaction between an aqueous solution of carbonic acid (H₂CO₃) and lithium hydroxide (LiOH) is: \(2 \mathrm{LiOH} + \mathrm{H}_{2}\mathrm{CO}_{3} \rightarrow \mathrm{Li}_{2}\mathrm{CO}_{3} + 2 \mathrm{H}_{2}\mathrm{O}\).

Step by step solution

01

Identify the products of the reaction

In this reaction, H₂CO₃ and LiOH will exchange their ions, forming lithium carbonate (Li₂CO₃) and water (H₂O).
02

Write the unbalanced equation

Now that we know the products formed in the reaction, we can write the unbalanced equation: H₂CO₃ + LiOH → Li₂CO₃ + H₂O
03

Balance the chemical equation

To balance the equation, we will adjust the coefficients to make sure the number of atoms of each element is conserved: 2 LiOH + H₂CO₃ → Li₂CO₃ + 2 H₂O Now, the equation is balanced, as there are 2 Li atoms, 2 H atoms, and 1 CO₃ group on both sides of the equation. The balanced chemical equation for the reaction between an aqueous solution of carbonic acid (H₂CO₃) and lithium hydroxide (LiOH) is: 2 LiOH + H₂CO₃ → Li₂CO₃ + 2 H₂O

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