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Chapter 8: Problem 16

Write the intact-compound equation and the net ionic equation for the neutralization of aqueous hydrofluoric acid by aqueous calcium hydroxide. What is the name of the salt that forms?

Short Answer

Expert verified
The balanced intact-compound equation for the neutralization of aqueous hydrofluoric acid (HF) by aqueous calcium hydroxide (Ca(OH)\(_2\)) is: HF (aq) + Ca(OH)\(_2\)(aq) → CaF\(_2\)(s) + 2H2O (l) The net ionic equation is: H\(^+\)(aq) + F\(^-\)(aq) + Ca\(^{2+}\)(aq) + 2OH\(^-\)(aq) → CaF\(_2\)(s) + 2H2O (l) The salt formed is calcium fluoride (CaF\(_2\)).

Step by step solution

01

1. Write the balanced intact-compound equation

First, we need to write the balanced chemical equation for the neutralization reaction between hydrofluoric acid (HF) and calcium hydroxide (Ca(OH)\(_2\)): HF (aq) + Ca(OH)\(_2\)(aq) → CaF\(_2\)(s) + 2H2O (l)
02

2. Separate the intact-compound equation into individual ions

Now, let's dissociate the strong electrolytes (aqueous strong acids and bases) into their individual ions: HF (aq) → H\(^+\)(aq) + F\(^-\)(aq) Ca(OH)\(_2\)(aq) → Ca\(^{2+}\)(aq) + 2OH\(^-\)(aq)
03

3. Write the net ionic equation by eliminating spectator ions

We can now write the net ionic equation. Spectator ions, which do not participate in the reaction, are eliminated. In this case, there are no spectator ions, so we rewrite the previous ions and combine them to form the net ionic equation: H\(^+\)(aq) + F\(^-\)(aq) + Ca\(^{2+}\)(aq) + 2OH\(^-\)(aq) → CaF\(_2\)(s) + 2H2O (l)
04

4. Identify the salt formed and provide its name

In the balanced intact-compound equation, the salt formed is CaF\(_2\), which is called calcium fluoride.

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Most popular questions from this chapter

Balance each equation: (a) \(\mathrm{Zn}+\mathrm{HCl} \rightarrow \mathrm{ZnCl}_{2}+\mathrm{H}_{2}\) (b) \(\mathrm{Na}_{2} \mathrm{O}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{NaOH}\) (c) \(\mathrm{CH}_{4}+\mathrm{H}_{2} \mathrm{~S} \rightarrow \mathrm{CS}_{2}+\mathrm{H}_{2}\) (d) \(\mathrm{CO}+\mathrm{H}_{2} \rightarrow \mathrm{CH}_{3} \mathrm{O} \mathrm{H}\)

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