Chapter 8: Problem 35
Balance this chemical equation and assign it a reaction type: \(\mathrm{N}_{2} \mathrm{O}_{5}(g) \rightarrow \mathrm{NO}_{2}(g)+\mathrm{O}_{2}(g)\)
Short Answer
Expert verified
The balanced chemical equation is \(2N_2O_5(g) \rightarrow 4NO_2(g) + O_2(g)\) and the reaction type is a Decomposition Reaction.
Step by step solution
01
Count the atoms on each side of the equation
First, let's look at the number of nitrogen and oxygen atoms in the reactants and products of the given chemical equation.
On the reactant side, we have:
- 2 Nitrogen atoms
- 5 Oxygen atoms
On the product side, we have:
- 1 Nitrogen atom in \(NO_2\)
- 2 Oxygen atoms in \(NO_2\)
- 2 Oxygen atoms in \(O_2\)
02
Balance the Nitrogen atoms
Since there are 2 Nitrogen atoms in the reactant side and 1 Nitrogen atom in the product side, we can place a coefficient of 2 before the \(NO_2(g)\) to balance the Nitrogen atoms:
\[N_2O_5(g) \rightarrow 2NO_2(g) + O_2(g)\]
Now we have:
- 2 Nitrogen atoms on both sides (balanced)
03
Balance the Oxygen atoms
We have 4 Oxygen atoms in the product side from the 2 molecules of \(NO_2\), and 2 additional Oxygen atoms from the \(O_2\). To make sure there are 5 Oxygen atoms on the reactants side, we can adjust the equation as follows:
\[N_2O_5(g) \rightarrow 2NO_2(g) + \frac{1}{2}O_2(g)\]
Now, our equation is balanced in terms of atoms, but it is not allowed to have a fraction as a coefficient, so we can multiply the equation by 2 to get full numbers as coefficients:
\[2N_2O_5(g) \rightarrow 4NO_2(g) + O_2(g)\]
Now we have confirmed that the equation is balanced.
04
Determine the reaction type
In this reaction, we do not observe a transfer of electrons (redox) nor the formation of a precipitate or a new gas from two or more compounds (double displacement), nor new ions or compound from an acid and base (neutralization).
The reaction seems to be a decomposition reaction, where a single compound breaks down into two or more simpler substances.
So, the balanced chemical equation is:
\[2N_2O_5(g) \rightarrow 4NO_2(g) + O_2(g)\]
And the reaction type is:
Decomposition Reaction
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Decomposition Reaction
When we're dealing with chemical reactions, we often encounter a type of reaction known as a decomposition reaction. This is a process in which a single compound breaks apart into two or more simpler substances, typically when heated or treated with an electrical current. It's vital to recognize this pattern because it helps determine the products of the reaction and is integral to understanding the chemical behavior of compounds.
In our example, the compound \(\mathrm{N}_2\mathrm{O}_5\) decomposes into \(\mathrm{NO}_2\) and \(\mathrm{O}_2\), without combining with another compound or element. Decomposition reactions are essential in chemistry because they're the reverse of synthesis reactions, where simpler substances combine to form a more complex compound. Recognizing a decomposition reaction can help students understand how substances are broken down, which is key in fields like environmental science and materials engineering.
In our example, the compound \(\mathrm{N}_2\mathrm{O}_5\) decomposes into \(\mathrm{NO}_2\) and \(\mathrm{O}_2\), without combining with another compound or element. Decomposition reactions are essential in chemistry because they're the reverse of synthesis reactions, where simpler substances combine to form a more complex compound. Recognizing a decomposition reaction can help students understand how substances are broken down, which is key in fields like environmental science and materials engineering.
Chemical Reaction Types
Chemistry is full of different types of reactions, each with unique features and outcomes. Understanding the various chemical reaction types is crucial for students as it lays the groundwork for predicting the products of a reaction and the reactivity of substances. Apart from decomposition reactions, we have synthesis (or combination) reactions, single displacement reactions, double displacement reactions, and combustion reactions. Each type of reaction follows certain patterns in how reactants transform into products.
For instance, in a synthesis reaction, elements or simpler compounds combine to form a more complex compound. In contrast, single and double displacement reactions involve the exchange of one or multiple elements between compounds. In a combustion reaction, a substance typically reacts with oxygen to produce energy in the form of light or heat. By identifying the type of reaction, students can begin to unravel the intricacies of the chemical processes around us.
For instance, in a synthesis reaction, elements or simpler compounds combine to form a more complex compound. In contrast, single and double displacement reactions involve the exchange of one or multiple elements between compounds. In a combustion reaction, a substance typically reacts with oxygen to produce energy in the form of light or heat. By identifying the type of reaction, students can begin to unravel the intricacies of the chemical processes around us.
Stoichiometry
A core aspect of mastering chemistry is understanding stoichiometry, which involves the quantitative relationships between the amounts of reactants and products in a chemical reaction. It's a bit like a recipe: stoichiometry tells you how much of each ingredient (reactant) you need to get the desired amount of product.
In our exercise, stoichiometry is employed to ensure that the number of atoms of each element is conserved across the reaction. To balance chemical equations, we adjust coefficients to respect the Law of Conservation of Mass, which states that matter is neither created nor destroyed in a chemical reaction. This careful balancing act allows chemists to predict how much product can be formed from given reactants or how much of a reactant is needed to create a certain amount of product. Essential for calculations in lab work, pharmaceuticals, environmental chemistry, and industrial applications, stoichiometry is a gateway to understanding and applying chemical reactions in real-life scenarios.
In our exercise, stoichiometry is employed to ensure that the number of atoms of each element is conserved across the reaction. To balance chemical equations, we adjust coefficients to respect the Law of Conservation of Mass, which states that matter is neither created nor destroyed in a chemical reaction. This careful balancing act allows chemists to predict how much product can be formed from given reactants or how much of a reactant is needed to create a certain amount of product. Essential for calculations in lab work, pharmaceuticals, environmental chemistry, and industrial applications, stoichiometry is a gateway to understanding and applying chemical reactions in real-life scenarios.