Sodium chloride reacts with bromine gas, \(\mathrm{Br}_{2}\), to produce sodium bromide plus chlorine gas. Write a balanced equation for this reaction.

The reactants in this reaction are sodium chloride (NaCl) and bromine gas (Br₂). The products are sodium bromide (NaBr) and chlorine gas (Cl₂).

Place the reactants on the left-hand side and the products on the right-hand side, separated by an arrow. NaCl + Br₂ → NaBr + Cl₂

Check the number of atoms for each element on both sides of the equation. Then, adjust the coefficients to balance the equation. Na: 1 atom on the left, 1 atom on the right - balanced Cl: 1 atom on the left, 2 atoms on the right - not balanced Br: 2 atoms on the left, 1 atom on the right - not balanced To balance chlorine, we can add a coefficient of 2 in front of NaCl: 2NaCl + Br₂ → NaBr + Cl₂ Now, we have 2 Cl atoms on both sides. However, now we have 2 Na atoms on the left side, so we need to adjust the coefficient for NaBr as well: 2NaCl + Br₂ → 2NaBr + Cl₂ Finally, let's check the balance again: Na: 2 atoms on the left, 2 atoms on the right - balanced Cl: 2 atoms on the left, 2 atoms on the right - balanced Br: 2 atoms on the left, 2 atoms on the right - balanced

The balanced chemical equation for the reaction of sodium chloride with bromine gas is: 2NaCl + Br₂ → 2NaBr + Cl₂