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Chapter 8: Problem 8

\(\quad \mathrm{KBr}(a q)+\mathrm{Cl}_{2}(a q) \rightarrow \mathrm{KCl}(a q)+\mathrm{Br}_{2}(a q)\)

Short Answer

Expert verified
The given chemical equation was unbalanced. We balanced it by adjusting the coefficients to obtain equal numbers of K, Cl, and Br atoms on both sides of the equation. The balanced chemical equation is: \(2 \mathrm{KBr} + \mathrm{Cl}_{2} \rightarrow 2 \mathrm{KCl} + 2 \mathrm{Br}\).

Step by step solution

01

Identify the reactants and products

The reactants are the substances that are combined to initiate the chemical reaction. In this case, the reactants are KBr and Cl2. The products are the substances formed as a result of the chemical reaction, which are KCl and Br2.
02

Write the unbalanced chemical equation

We will write the equation as given, where the reactants are on the left side and the products on the right side of the arrow: \(\mathrm{KBr} + \mathrm{Cl}_{2} \rightarrow \mathrm{KCl} + \mathrm{Br}_{2}\)
03

Count the atoms on both sides of the equation

Before balancing, we need to count the number of atoms for each element on both sides of the equation. Reactants: - 1 K atom - 1 Br atom - 2 Cl atoms Products: - 1 K atom - 1 Cl atom - 2 Br atoms
04

Balance the equation

We can see that the number of Cl and Br atoms are not equal on both sides of the equation. We'll start by balancing the Br atoms: \(\mathrm{KBr} + \mathrm{Cl}_{2} \rightarrow \mathrm{KCl} + 2 \mathrm{Br}\) Now, the equation has: Reactants: - 1 K atom - 1 Br atom - 2 Cl atoms Products: - 1 K atom - 1 Cl atom - 2 Br atoms To balance the Cl atoms, we need to multiply KCl by 2: \(2 \mathrm{KBr} + \mathrm{Cl}_{2} \rightarrow 2 \mathrm{KCl} + 2 \mathrm{Br}\) Now, the equation has: Reactants: - 2 K atoms - 2 Br atoms - 2 Cl atoms Products: - 2 K atoms - 2 Cl atoms - 2 Br atoms
05

Check if the equation is balanced

After balancing the equation, we can observe that there are equal numbers of K, Br, and Cl atoms on both sides of the equation. Therefore, the balanced chemical equation is: \(2 \mathrm{KBr} + \mathrm{Cl}_{2} \rightarrow 2 \mathrm{KCl} + 2 \mathrm{Br}\)

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Most popular questions from this chapter

Write the balanced chemical equation for the reaction between pentane, \(\mathrm{C}_{5} \mathrm{H}_{12}\), and oxygen gas that produces carbon dioxide and water.

Balance this equation and classify it as combination, decomposition, single- replacement, or double-replacement: \(\mathrm{K}_{2} \mathrm{CrO}_{4}+\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3} \rightarrow \mathrm{Al}_{2}\left(\mathrm{CrO}_{4}\right)_{3}+\mathrm{KNO}_{3}\)

A solution containing which anion can be added to separate: (a) \(\mathrm{Na}^{+}(a q)\) from \(\mathrm{Ag}^{+}(a q)\) (b) \(\mathrm{Na}^{+}(a q)\) from \(\mathrm{Ca}^{2+}(a q)\)

Consider the following chemical equation: \(\mathrm{C}_{2} \mathrm{H}_{2}+\mathrm{O}_{2} \rightarrow \mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2}\) (a) Balance this chemical equation by inspection. (b) Translate the balanced equation into words. The compound \(\mathrm{C}_{2} \mathrm{H}_{2}\) is called acetylene and is used as a fuel for torches that cut through steel.

Suppose you had oxalic acid, \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\), and you wanted to make sodium oxalate, \(\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4} .\) How might you do this?
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