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Chapter 8: Problem 87

Classify each compound as acid, base, or salt: (a) \(\mathrm{KCl}\) (b) \(\mathrm{CH}_{3} \mathrm{COOH}\) (c) \(\mathrm{Al}(\mathrm{OH})_{3}\) (d) \(\mathrm{H}_{3} \mathrm{BO}_{3}\) (e) \(\mathrm{LiC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\)

Short Answer

Expert verified
(a) \(\mathrm{KCl}\): salt (b) \(\mathrm{CH}_{3} \mathrm{COOH}\): acid (c) \(\mathrm{Al}(\mathrm{OH})_{3}\): base (d) \(\mathrm{H}_{3} \mathrm{BO}_{3}\): acid (e) \(\mathrm{LiC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\): salt

Step by step solution

01

Determine the type of compound a: \(\mathrm{KCl}\)

We see that \(\mathrm{KCl}\) does not contain an \(\mathrm{H}\) in the front of the formula or an \(\mathrm{OH^-}\) group. It is, therefore, classified as a salt.
02

Determine the type of compound b: \(\mathrm{CH}_{3} \mathrm{COOH}\)

The chemical formula \(\mathrm{CH}_{3} \mathrm{COOH}\) has an \(\mathrm{H}\) in the front, but it does not contain a hydroxide group \(\mathrm{(OH^-)}\). Therefore, it is classified as an acid.
03

Determine the type of compound c: \(\mathrm{Al}(\mathrm{OH})_{3}\)

The chemical formula \(\mathrm{Al}(\mathrm{OH})_{3}\) contains the hydroxide group \(\mathrm{(OH^-)}\), which indicates that it is a base.
04

Determine the type of compound d: \(\mathrm{H}_{3} \mathrm{BO}_{3}\)

The chemical formula \(\mathrm{H}_{3} \mathrm{BO}_{3}\) has an \(\mathrm{H}\) in the front, but it does not contain a hydroxide group \(\mathrm{(OH^-)}\). Therefore, it is classified as an acid.
05

Determine the type of compound e: \(\mathrm{LiC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\)

The chemical formula of \(\mathrm{LiC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\) neither starts with an \(\mathrm{H}\) nor contains a hydroxide group \(\mathrm{(OH^-)}\). Therefore, it is classified as a salt.

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Most popular questions from this chapter

You need to prepare some calcium nitrate. (a) Write an intact-molecule balanced equation for an acid-base neutralization reaction that could be used to prepare calcium nitrate. (b) Write the net ionic equation for the neutralization.

Consider the following unbalanced chemical equation: \(\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}_{2}(1)+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g)\) (a) Balance this equation. (b) Classify the reaction type and explain. (c) Because one of the reactants is oxygen, what can you call this type of reaction?

Calcium hydroxide can be used as an antacid to neutralize \(\mathrm{HCl}\), the acid found in the stomach. Water and calcium chloride, \(\mathrm{CaCl}_{2}\), are the products of the reaction. Write the balanced equation for the reaction.

Write (a) a reaction with all species intact and using \((a q),(s)\), or \((l)\) for the reaction between aqueous solutions of sulfuric acid and calcium hydroxide. (b) What salt is formed as a result of neutralization?

When a precipitate forms in water, the water often becomes warmer. What is the source of the heat energy that warms the water?
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