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Chapter 8: Problem 9

\(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{~s}) \stackrel{\text { Heat }}{\longrightarrow} \mathrm{PbO}(\mathrm{s})+\mathrm{NO}(\mathrm{g})+\mathrm{O}_{2}(g)\)

Short Answer

Expert verified
When solid lead (II) nitrate (Pb(NO3)2) is heated, it undergoes thermal decomposition and breaks down into solid lead oxide (PbO), nitrogen monoxide gas (NO), and oxygen gas (O2). The balanced chemical equation for this process is: \[Pb(NO_{3})_{2}(s) \stackrel{\text{Heat}}{\longrightarrow} PbO(s) + NO(g) + O_{2}(g)\]

Step by step solution

01

Identify reactants and products

In the given chemical equation, we have one reactant and three products: Reactant: Lead (II) nitrate, which is represented by the chemical formula Pb(NO3)2 Products: Lead oxide (PbO), nitrogen monoxide (NO), and oxygen gas (O2)
02

Interpret coefficients and states of the substances involved

In the balanced chemical equation, we can see that there are no numerical coefficients in front of the substances, meaning they all have a coefficient of 1. This indicates that one mole of lead (II) nitrate decomposes into one mole of each product. Regarding the states of the substances, we see that: - Lead (II) nitrate, Pb(NO3)2, is a solid (s) - Lead oxide, PbO, is also a solid (s) - Nitrogen monoxide, NO, is a gas (g) - Oxygen gas, O2, is also a gas (g)
03

Describe the process of thermal decomposition

Based on the given information, the process of thermal decomposition of lead (II) nitrate is as follows: When lead (II) nitrate is heated, it breaks down into lead oxide, nitrogen monoxide, and oxygen gas. The solid lead (II) nitrate becomes solid lead oxide, while the nitrogen and oxygen molecules are released as gases.

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