Chapter 9: Problem 137
If you have \(200.0 \mathrm{~g}\) of dinitrogen pentoxide, how many atoms of nitrogen do you have? How many atoms of oxygen do you have?
Short Answer
Expert verified
In 200g of dinitrogen pentoxide (N2O5), there are approximately \(2.23 \times 10^{24}\) atoms of nitrogen and \(5.57 \times 10^{24}\) atoms of oxygen.
Step by step solution
01
Calculate the number of moles of dinitrogen pentoxide (N2O5)
The first step is to calculate the number of moles of N2O5 in 200g by using the formula:
moles = mass (g) / molar mass (g/mol)
The molar mass of N2O5 = (2 * molar mass of N) + (5 * molar mass of O) = (2 * 14.007) + (5 * 15.999) = 108.01 g/mol.
Now we can find the moles of N2O5:
moles of N2O5 = 200g / 108.01 g/mol ≈ 1.85 moles
02
Use stoichiometry to find the moles of nitrogen and oxygen atoms
We know that 1 mole of N2O5 contains 2 moles of N atoms and 5 moles of O atoms. So, from the moles of N2O5 calculated in step 1, we can find the moles of nitrogen and oxygen atoms using stoichiometry:
moles of N atoms = (2 moles of N / 1 mole of N2O5) * 1.85 moles of N2O5 ≈ 3.70 moles of N
moles of O atoms = (5 moles of O / 1 mole of N2O5) * 1.85 moles of N2O5 ≈ 9.25 moles of O
03
Convert moles of nitrogen and oxygen atoms to the number of atoms using Avogadro's number
Now, we can convert the moles of N and O atoms to the number of atoms using Avogadro's number (6.022 x 10^23 atoms/mol):
Number of N atoms = 3.70 moles * 6.022 x 10^23 atoms/mol ≈ 2.23 x 10^24 N atoms
Number of O atoms = 9.25 moles * 6.022 x 10^23 atoms/mol ≈ 5.57 x 10^24 O atoms
In conclusion, there are approximately \(2.23 \times 10^{24}\) atoms of nitrogen and \(5.57 \times 10^{24}\) atoms of oxygen in 200g of dinitrogen pentoxide (N2O5).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molar Mass Calculation
Understanding molar mass calculation is crucial for anyone looking to delve into the world of chemistry. Simply put, the molar mass of a substance is the mass of one mole of that substance. It is typically expressed in grams per mole (g/mol) and can be considered as the 'gram formula mass' when dealing with ionic compounds.
Let's break it down with an example. In the exercise, we calculate the molar mass of dinitrogen pentoxide (N2O5). To do this, we sum the masses of each atom present in the compound, multiplied by their respective quantities. With nitrogen (N) having an atomic mass of approximately 14.007 g/mol and oxygen (O) having a mass of about 15.999 g/mol, the molar mass of N2O5 can be calculated as follows:
Let's break it down with an example. In the exercise, we calculate the molar mass of dinitrogen pentoxide (N2O5). To do this, we sum the masses of each atom present in the compound, multiplied by their respective quantities. With nitrogen (N) having an atomic mass of approximately 14.007 g/mol and oxygen (O) having a mass of about 15.999 g/mol, the molar mass of N2O5 can be calculated as follows:
- (2 atoms of N) * (14.007 g/mol for N) = 28.014 g/mol for N
- (5 atoms of O) * (15.999 g/mol for O) = 79.995 g/mol for O
Avogadro's Number
Getting to grips with Avogadro's number is a bit like unlocking a secret door to the molecular world. Often symbolized as 6.022 x 10^23, Avogadro's number represents the quantity of particles found in one mole of a substance. These particles could be atoms, molecules, ions, or electrons, depending on the context.
Let's place this into the context of our exercise. Once the number of moles of nitrogen and oxygen atoms in our N2O5 are calculated, we can use Avogadro's number to convert these moles into actual atoms--which is pretty mind-blowing if you think about it! This constant allows us to take what we know at the macroscopic level (like grams of a compound) and translate that into microscopic insights, giving us the number of atoms or molecules involved. It encompasses the bridge between the observable world and the atomic or molecular scale.
Let's place this into the context of our exercise. Once the number of moles of nitrogen and oxygen atoms in our N2O5 are calculated, we can use Avogadro's number to convert these moles into actual atoms--which is pretty mind-blowing if you think about it! This constant allows us to take what we know at the macroscopic level (like grams of a compound) and translate that into microscopic insights, giving us the number of atoms or molecules involved. It encompasses the bridge between the observable world and the atomic or molecular scale.
Moles to Atoms Conversion
The moles to atoms conversion is a straightforward yet indispensable tool in chemistry. It relies fundamentally on understanding Avogadro's number. To convert moles to atoms, you simply multiply the number of moles you have by Avogadro's constant, 6.022 x 10^23 atoms/mol.
In the exercise, we performed two separate conversions—first for nitrogen atoms, then for oxygen atoms. Here’s how it looks in a nutshell:
In the exercise, we performed two separate conversions—first for nitrogen atoms, then for oxygen atoms. Here’s how it looks in a nutshell:
- For nitrogen: 3.70 moles of N * 6.022 x 10^23 atoms/mol = 2.23 x 10^24 atoms of N.
- For oxygen: 9.25 moles of O * 6.022 x 10^23 atoms/mol = 5.57 x 10^24 atoms of O.