Succinic acid, an intermediate in the metabolism of certain foods, has a molecular mass of \(118.1 \mathrm{~g} / \mathrm{mole}\). A \(1.926 \mathrm{~g}\) sample of succinic acid \(\left(\mathrm{H}_{x} \mathrm{Suc}\right)\) reacts with exactly \(1.25 \mathrm{~g}\) of \(\mathrm{NaOH}\) according to the following balanced equation: \(\mathrm{H}_{x} \mathrm{Suc}+x \mathrm{NaOH} \rightarrow \mathrm{Na}_{x} \mathrm{Suc}+x \mathrm{H}_{2} \mathrm{O}\) What is the value of \(x\) ?

Short Answer

Expert verified
The value of x is approximately \(2\), which means that 2 moles of NaOH react with 1 mole of succinic acid in the given reaction.

Step by step solution

01

Calculate the moles of succinic acid

To find the moles of succinic acid, use the given mass of the sample and its molar mass: Moles of succinic acid = (Mass of succinic acid) / (Molar Mass of succinic acid) Moles of succinic acid = \( \frac{1.926 g}{118.1 g/mol} \)
02

Calculate the moles of NaOH

Similarly, we need to find the moles of NaOH using its given mass and molar mass: Moles of NaOH = (Mass of NaOH) / (Molar Mass of NaOH) Molar Mass of NaOH = 22.99 g/mol (Na) + 15.999 g/mol (O) + 1.00784 g/mol (H) = 40.00 g/mol Moles of NaOH = \( \frac{1.25 g}{40.00 g/mol} \)
03

Find the stoichiometric ratio

In the balanced equation: \( \mathrm{H}_{x} \mathrm{Suc} + x \mathrm{NaOH} \rightarrow \mathrm{Na}_{x} \mathrm{Suc} + x \mathrm{H}_{2} \mathrm{O} \) For every mole of succinic acid, x moles of NaOH react. So, to find the value of 'x', we need to find the stoichiometric ratio: x = Moles of NaOH / Moles of succinic acid Now, let's plug in the values from step 1 and 2:
04

Calculate the value of x

x = \( \frac{ \frac{1.25}{40} }{ \frac{1.926}{118.1} }\) After solving the fractions: x ≈ 2 So, the value of x is approximately 2, which means that 2 moles of NaOH react with 1 mole of succinic acid in the given reaction.

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