What is the mass percent of each element in trinitrotoluene (TNT), \(\mathrm{C}_{7} \mathrm{H}_{5} \mathrm{~N}_{3} \mathrm{O}_{6}\) ?

Short Answer

Expert verified
The mass percent composition of trinitrotoluene (TNT) is: Carbon (C) = \(\dfrac{7 × 12.01}{\text{Molar mass of TNT}}\) × 100%, Hydrogen (H) = \(\dfrac{5 × 1.008}{\text{Molar mass of TNT}}\) × 100%, Nitrogen (N) = \(\dfrac{3 × 14.01}{\text{Molar mass of TNT}}\) × 100%, and Oxygen (O) = \(\dfrac{6 × 16.00}{\text{Molar mass of TNT}}\) × 100%.

Step by step solution

01

Calculate the molar mass of TNT

First, we will calculate the molar mass of TNT \((\mathrm{C}_{7} \mathrm{H}_{5} \mathrm{N}_{3} \mathrm{O}_{6})\). Using the atomic weights of Carbon (C), Hydrogen (H), Nitrogen (N), and Oxygen (O), we can find the molar mass of TNT. Molar mass of TNT = (7 × Atomic weight of C) + (5 × Atomic weight of H) + (3 × Atomic weight of N) + (6 × Atomic weight of O) Using the atomic weights: - Carbon (C) = 12.01 g/mol - Hydrogen (H) = 1.008 g/mol - Nitrogen (N) = 14.01 g/mol - Oxygen (O) = 16.00 g/mol Molar mass of TNT = (7 × 12.01 g/mol) + (5 × 1.008 g/mol) + (3 × 14.01 g/mol) + (6 × 16.00 g/mol)
02

Calculate the molar mass of each element in TNT

Now, we will calculate the total molar mass of each element in TNT using their respective atomic weights and the number of atoms. For Carbon (C) in TNT: (7 × 12.01 g/mol) For Hydrogen (H) in TNT: (5 × 1.008 g/mol) For Nitrogen (N) in TNT: (3 × 14.01 g/mol) For Oxygen (O) in TNT: (6 × 16.00 g/mol)
03

Calculate the mass percent of each element

We will now calculate the mass percent of each element using the formula: Mass percent of an element = (\(\dfrac{\text{molar mass of the element}}{\text{molar mass of TNT}}\)) × 100% For Carbon (C): Mass percent of C = (\(\dfrac{7 × 12.01}{\text{Molar mass of TNT}}\)) × 100% For Hydrogen (H): Mass percent of H = (\(\dfrac{5 × 1.008}{\text{Molar mass of TNT}}\)) × 100% For Nitrogen (N): Mass percent of N = (\(\dfrac{3 × 14.01}{\text{Molar mass of TNT}}\)) × 100% For Oxygen (O): Mass percent of O = (\(\dfrac{6 × 16.00}{\text{Molar mass of TNT}}\)) × 100% By calculating the mass percent of each element, we will find the mass percent composition of trinitrotoluene (TNT).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass
Understanding molar mass is fundamental when studying chemistry, as it connects the world of the very small, atoms and molecules, to the scales we can observe. The molar mass of a substance is the weight in grams of one mole of the substance. One mole represents Avogadro's number, which is approximately 6.022 x 1023 particles.

It is calculated by summing the atomic weights of each atom within a molecule, usually represented in grams per mole (g/mol). Consider water (H2O), with its molecular formula indicating two hydrogen atoms and one oxygen atom. Thus, its molar mass is the sum of twice the molar mass of hydrogen (2 x 1.008 g/mol) and the molar mass of oxygen (16.00 g/mol), resulting in approximately 18.016 g/mol for water.
Atomic Weight
Atomic weight, also known as the relative atomic mass, is the ratio of the average mass of atoms of an element to 1/12th the mass of carbon-12. It's measured in atomic mass units (amu), and it's a key concept because it allows chemists to talk about atoms in a way that is independent of the number of atoms being discussed.

Elements on the periodic table are listed with their atomic weights, allowing for quick reference. As seen in the TNT example, each element such as carbon (C), hydrogen (H), nitrogen (N), and oxygen (O) has its distinct atomic weight. These values are crucial when calculating molar masses and percent compositions in compounds.
Percent Composition
Percent composition by mass represents the percent by mass of each element within a compound. This is particularly useful for understanding the makeup of a chemical substance. In the case of TNT, the previous solution outlines how each element's mass contribution is calculated as a percentage of the total compound's mass.

The formula \(\frac{molar mass \, of \, element}{molar mass \, of \, compound}\) multiplied by 100% gives us this percent composition. It's important to calculate this for each element in the compound to provide a comprehensive view of the chemical substance's makeup.
Chemical Formula
A chemical formula offers a concise way to express the information about the atoms that constitute a particular chemical compound. It identifies each element by its chemical symbol and indicates the number of atoms of the element found in one discrete molecule of the substance. For example, TNT's formula C7H5N3O6 shows it is made up of carbon, hydrogen, nitrogen, and oxygen in a specific ratio.

This ratio is essential in calculating both the molar mass and the percent composition. The chemical formula serves as the blueprint from which we derive much of our quantitative information about the substance at hand. By understanding the chemical formula, students can better understand how to approach exercises involving molar mass and percent composition.

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Most popular questions from this chapter

A \(1.000-g\) sample of a liquid that contains only carbon and hydrogen burns in oxygen to produce \(1.284 \mathrm{~g}\) of \(\mathrm{H}_{2} \mathrm{O}\) (a) What are the mass percents of the elements present in this sample? (b) What is the empirical formula for this compound? (c) The molar mass of this compound is determined to be about \(71 \mathrm{~g} / \mathrm{mol}\). What is the molecular formula for this compound? (Hint: When attempting this problem, understand that all of the carbon in the compound burned ends up as \(\mathrm{CO}_{2}\), and all of the hydrogen in the compound burned ends up as \(\mathrm{H}_{2} \mathrm{O}\). Also, there is only 1 mole of \(C\) per mole of \(\mathrm{CO}_{2}\), but there are 2 moles of \(\mathrm{H}\) per mole of \(\mathrm{H}_{2} \mathrm{O} .\) )

What is the maximum possible value of the percent yield of a chemical reaction?

The compound \(\mathrm{P}_{4} \mathrm{O}_{10}\) has an empirical formula of \(\mathrm{P}_{2} \mathrm{O}_{5} .\) By what factor will the percent by mass composition differ for each element between these two formulas? Explain your answer.

Consider a \(5.00-\mathrm{g}\) sample of silver nitrate, \(\mathrm{AgNO}_{3}(s)\) (a) How many moles of \(\mathrm{AgNO}_{3}\) are in this sample? (b) How many moles of \(\mathrm{O}\) are in this sample? (c) How many grams of \(\mathrm{N}\) are in this sample? (d) How many Ag atoms are in this sample?

Consider the following unbalanced combustion reaction:(a) Balance the equation. (b) How many moles of \(\mathrm{CO}_{2}\) will be generated from using excess methane and \(5.0\) moles of \(\mathrm{O}_{2} ?\) (c) How many molecules of \(\mathrm{CO}_{2}\) will be produced from using excess methane and \(5.0 \mathrm{~g}\) of \(\mathrm{O}_{2}\) ?

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