Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 9: Problem 38

How is the concept of " 1 mole" similar to the concept of " 1 dozen"?

Short Answer

Expert verified
Both the concepts of "1 mole" and "1 dozen" are similar as they are counting units used to represent fixed numbers of entities and simplify large numbers. A mole represents \(6.022 \times 10^{23}\) entities (atoms, molecules, or ions) in chemistry, while a dozen represents 12 entities (such as eggs, pencils, or any other items).

Step by step solution

01

Definition of a Mole and a Dozen

A mole is a unit of measurement in chemistry, used to express amounts of a chemical substance. It is defined as the amount of a substance that contains the same number of atoms, molecules, or ions as there are in 12 grams of carbon-12. One mole contains approximately \(6.022 \times 10^{23}\) entities (known as Avogadro's number). A dozen is a unit used for counting items, and it's equal to 12 of those items. For example, when you say one dozen eggs, you mean 12 eggs.
02

Similarity #1: Both are counting units

Both mole and dozen are used as counting units. A mole is a unit of measurement for chemical substances, whereas a dozen is a general unit used for counting any group of items.
03

Similarity #2: Both are used to express a fixed number of entities

Both mole and dozen represent fixed numbers. One mole represents \(6.022 \times 10^{23}\) entities (atoms, molecules, or ions), while one dozen represents 12 entities (such as eggs, pencils, or any other items).
04

Similarity #3: Both simplify large numbers

The concept of a mole is used to simplify extremely large numbers of particles in chemistry. Similarly, a dozen is used to simplify the counting of items. For instance, it's easier to say one mole of water molecules or one dozen donuts instead of expressing the exact number of entities in each case. In conclusion, both the concepts of "1 mole" and "1 dozen" are similar in that they are counting units used to represent fixed numbers of entities and simplify large numbers.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Sodium metal reacts with water to form aqueous sodium hydroxide and hydrogen gas. (a) Write a balanced chemical equation for this reaction. (b) Which reactant is limiting if \(100.0 \mathrm{~g}\) of \(\mathrm{Na}\) and \(4.00\) moles of water are used?

The amino acid arginine is made up of \(41.37 \%\) by mass \(\mathrm{C}, 8.10 \%\) by mass \(\mathrm{H}, 32.16 \%\) by mass \(\mathrm{N}\), and \(18.37 \%\) by mass \(\mathrm{O}\). If the molar mass of arginine is approximately \(174 \mathrm{~g} / \mathrm{mol}\), what is its molecular formula?

Consider the following balanced chemical equation: \(2 \mathrm{H}_{2}+\mathrm{O}_{2} \rightarrow 2 \mathrm{H}_{2} \mathrm{O}\) (a) How many grams of water are formed from \(5.00 \mathrm{~g}\) of \(\mathrm{H}_{2}\) and an excess amount of \(\mathrm{O}_{2}\) ? (b) How many grams of \(\mathrm{O}_{2}\) do you need to produce \(5.00 \mathrm{~g}\) of \(\mathrm{H}_{2} \mathrm{O}\) ? (c) Given \(100.0 \mathrm{~g}\) of \(\mathrm{H}_{2}\), how many grams of \(\mathrm{O}_{2}\) are required to run the reaction in a stoichiometric fashion? (d) What is the theoretical yield in grams of water upon combining \(50.0 \mathrm{~g}\) of \(\mathrm{O}_{2}\) with an excess amount of \(\mathrm{H}_{2}\) ? (e) Express the answer to part (d) in terms of the number of water molecules.

Silicon nitride, \(\mathrm{Si}_{3} \mathrm{~N}_{4}\), is a ceramic material capable of withstanding high temperatures. It can be produced using the following unbalanced reaction: \(\mathrm{SiCl}_{4}+\mathrm{NH}_{3} \rightarrow \mathrm{Si}_{3} \mathrm{~N}_{4}+\mathrm{HCl}\) If \(64.2 \mathrm{~g}\) of \(\mathrm{SiCl}_{4}\) is reacted with \(20.0 \mathrm{~g}\) of \(\mathrm{NH}_{3}\), how many grams of \(\mathrm{Si}_{3} \mathrm{~N}_{4}\) are produced if the reaction has a \(96.0 \%\) yield?

Potassium nitrate decomposes upon heating to form potassium oxide, nitrogen gas, and oxygen gas. If \(19.6 \mathrm{~g}\) of potassium nitrate have decomposed, how many molecules of oxygen gas have been formed?
See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

Chemical Analysis

Read Explanation

The Earths Atmosphere

Read Explanation

Making Measurements

Read Explanation

Physical Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free