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Chapter 9: Problem 54

Consider the ammonia \(\left(\mathrm{NH}_{3}\right)\) molecule. (a) If you have 1 mole of ammonia, how many moles of \(\mathrm{H}\) atoms do you have? (b) If you have 2 moles of ammonia, how many moles of \(\mathrm{H}\) atoms do you have? (c) If you have 2 moles of ammonia, how many N atoms do you have? (We are not asking for moles here.)

Short Answer

Expert verified
(a) In 1 mole of ammonia (NH₃), there are 3 moles of H atoms, since the mole ratio for H: NH₃ is 3:1. (b) In 2 moles of ammonia (NH₃), there are 6 moles of H atoms, using the same mole ratio. (c) In 2 moles of ammonia (NH₃), there are approximately \(1.2044 \times 10^{24}\) N atoms, with the knowledge that the mole ratio for N: NH₃ is 1:1 and applying Avogadro's number (6.022 x 10²³ atoms/mol).

Step by step solution

01

Mole ratio of H in ammonia

There are three hydrogen atoms (H) in one ammonia molecule (NH₃). So the mole ratio is 3:1 for H: NH₃. That means, for every mole of NH₃, there are 3 moles of H atoms.
02

Calculating moles of H atoms

We have 1 mole of ammonia (NH₃). Using the mole ratio (3:1), we calculate the number of moles of H atoms by multiplying the number of moles of NH₃ by 3: moles of H = moles of NH₃ × 3 moles of H = 1 × 3 moles of H = 3 Therefore, there are 3 moles of H atoms present in 1 mole of ammonia. (b) 2 moles of NH₃, how many moles of H atoms
03

Calculating moles of H atoms

We have 2 moles of ammonia (NH₃). Using the mole ratio (3:1), we calculate the number of moles of H atoms by multiplying the number of moles of NH₃ by 3: moles of H = moles of NH₃ × 3 moles of H = 2 × 3 moles of H = 6 Therefore, there are 6 moles of H atoms present in 2 moles of ammonia. (c) 2 moles of NH₃, how many N atoms (we're not asking for moles)
04

Mole ratio of N in ammonia

There is one nitrogen atom (N) in one ammonia molecule (NH₃). So the mole ratio is 1:1 for N: NH₃.
05

Calculating nitrogen atoms from moles of NH₃

We have 2 moles of ammonia (NH₃). Using the mole ratio (1:1) and Avogadro's number (6.022 x 10²³ atoms/mol), we calculate the number of N atoms: N atoms = moles of NH₃ x Avogadro's number N atoms = 2 x (6.022 x 10²³) N atoms = 12.044 x 10²³ N atoms = 1.2044 x 10²⁴ Hence, there are approximately \(1.2044 \times 10^{24}\) N atoms present in 2 moles of ammonia.

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