Are the linear combinations \(2 x-y-z, 2 y-x-z\) \(2 z-x-y\) linearly independent?

Short Answer

Expert verified
The vectors \(2 x-y-z, 2 y-x-z, 2 z-x-y\) are linearly dependent.

Step by step solution

01

Set Up a Matrix with the Given Vectors

The first step is to set up a matrix using the coefficients of the vectors. This will result in the following matrix A:\n\[ A = \begin{bmatrix} 2 & -1 & -1 \ -1 & 2 & -1 \ -1 & -1 & 2 \end{bmatrix} \]
02

Calculating the determinant

To check for linear independence, compute the determinant of the matrix. If the determinant is nonzero, the vectors are linearly independent. Calculate the determinant (det(A)), using the co-factor method or Sarrus' rule. \n\[ det(A) = 2((2*2 - (-1*-1)) - (-1)(-1*2 - (-1*-1)) + (-1)(-1*-1 - 2*-1))\] \[ = 2(4 -1) - (-1)(-2-1) + (-1)(-1 -2) \]\[ = 2(3) - (-1*-3) - 3\] \[ = 6 -3 -3 = 0 \]
03

Check the determinant

Check the computed determinant of A. If it equals to zero, this means the vectors are linearly dependent. The determinant we found is 0.

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