A particle in an infinite one-dimensional system was described by the wavefunction \(\psi(x)=\mathrm{Ne}^{-x^{2} / 2 r^{2}}\). Normalize this function. Calculate the probability of finding the particle in the range \(-\Gamma \leq x \leq \Gamma\). Hint. The integral encountered in the second part is the error function. It is available in mathematical software.

Short Answer

Expert verified
The normalized function is \( \psi_{normalized}(x) = e^{-x^{2} / 2 r^{2}}/\sqrt{π}r \) and probability of finding the particle in the range \( -\Gamma \leq x \leq \Gamma \) is \( \frac{2}{\sqrt{π}} erf(\Gamma / r) \).

Step by step solution

01

Normalizing the function

To normalize the function, firstly need to find \( |\psi(x)|^{2} \) which is \( |Ne^{-x^{2} / 2 r^{2}}|^{2} = N^{2}e^{-x^{2}/r^{2}} \). Then, we set the integral over all space of this equal to one, \[ \int_{-\infty}^{\infty} N^{2}e^{-x^{2}/r^{2}} dx = 1 \]. Solving the integral gives \( N^{2}\sqrt{π}r = 1 \). Hence, \( N = 1/\sqrt{π}r \) and our normalized wave function is \( \psi_{normalized}(x) = e^{-x^{2} / 2 r^{2}}/\sqrt{π}r \).
02

Computing the probability

Now that we have the normalized wave function, we can compute the probability of finding the particle in the range \( -\Gamma \leq x \leq \Gamma \) by integrating the probability density over that range. The probability is computed as \[ \int_{-\Gamma}^{\Gamma} |\psi_{normalized}(x)|^{2} dx = \int_{-\Gamma}^{\Gamma} \frac{e^{-x^{2}/r^{2}}}{πr^{2}} dx \]. The integral here is the error function, often denoted as \( erf(x) \), and its value can be found using mathematical software. Hence the result will be \( \frac{2}{\sqrt{π}} erf(\Gamma / r) \).

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