The rotational constant of \(^{1} \mathrm{H}^{35} \mathrm{Cl}\) is \(10.4400 \mathrm{cm}^{-1}\) in the ground vibrational state and \(10.1366 \mathrm{cm}^{-1}\) in the state \(v=1 .\) Plot the wavenumbers of the \(\mathrm{P}\) -, \(\mathrm{Q}\) -, and \(\mathrm{R}\) -branches against \(J\) as a representation of the structure of the \(1-0\) transition. Take \(\tilde{v}=2990.95 \mathrm{cm}^{-1}\) and neglect anharmonicity. (The Q-branch is not observed.)

Short Answer

Expert verified
The structure of the \(1-0\) transition can be represented by plotting the wavenumbers of P and R branches, calculated by using the given formulas, against the corresponding rotational quantum numbers \(J\). As \(J\) increases, the wavenumbers decrease for the P-branch and increase for the R-branch, forming characteristic 'X' shape. The Q-branch is not observed.

Step by step solution

01

Understand the query

We are provided the rotational constants \(B_0\) and \(B_1\) for a molecule in its ground and first vibrational states respectively. We are also given the vibrational wavenumber (\(\tilde{v} \)). Our task is to calculate and plot the wavenumbers (\(\bar{\nu}\)) for the P, Q and R branches of the \(1-0\) transition against the rotational quantum number \(J\). The P, Q, and R branches usually correspond to \(\Delta J = -1, 0, +1\) transitions respectively. For the P and R branches, the wavenumber \(\bar{\nu}\) is given by \(\bar{\nu} = \tilde{v} + (2B_1 - 4B_0)J + 2B_1\) for the R branch and \(\bar{\nu} = \tilde{v} - (2B_0 + 4B_1)J - 2B_0\) for the P branch. Here, \(\Delta J = J_{\text{final}} - J_{\text{initial}}\). For the Q branch, \(\Delta J = 0\), so the wavenumber is just the vibrational frequency \(\tilde{v}\). As given in the problem, the Q branch is not observed. Assuming the anharmonicity is negligible, we can ignore any effects due to this.
02

Calculation of wavenumbers

Now using the formulas for the wavenumbers of the P and R branches and the given values, we can evaluate these for different \(J\). For example, for \(J = 0\), the wavenumber for P branch will be \(\tilde{v} - 2B_0\) and for R branch will be \(\tilde{v} + 2B_1\). For \(J = 1\), it will be \(\tilde{v} - (2B_0 + 4B_1)\) for P branch and \(\tilde{v} + (2B_1 - 4B_0)\) for the R branch. Similarly, we can continue computing these for higher \(J\) to get the set of data points. Remember, \(J\) must be a positive integer.
03

Plotting wavenumbers against \(J\)

Now, we can plot the wavenumbers calculated above against the corresponding \(J\). This will give us a representation of the structure of the \(1-0\) transition. There will be two lines, one for each of the P and R branches. As \(\Delta J\) increases (moving away from \(J=0\)), the wavenumbers will decrease for the P branch and increase for the R branch, forming a characteristic 'X' shape. The wavenumbers for the Q-branch are not observed.

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Most popular questions from this chapter

Determine all of the symmetry species spanned by the normal modes of chlorofluoromethane.

The \(Q\) -branch line of the fundamental transition of a diatomic molecule lies at \(3142.3 \mathrm{cm}^{-1}\). The first line in the P-branch (that is, the P-branch line closest to the Q-branch) is displaced in magnitude by \(21.2 \mathrm{cm}^{-1}\) from the Q-branch. (a) Neglecting the effects of anharmonicity and centrifugal distortion, compute \(v\) and \(\bar{B}\). Assume that the rotational constant is independent of the vibrational level. (b) Predict the wavenumber of the next P-branch line. (c) Predict the wavenumber of the \(R\) -branch line closest to the Q-branch. (d) If centrifugal distortion is considered, will the first \(\mathrm{P}\) branch line be found at a higher, lower, or the same wavenumber as in part (a)?

Show that the rotational energy levels of a square planar \(\mathrm{AB}_{4}\) molecule may be expressed solely in terms of the rotational constant \(\bar{B}\).

Consider a two-dimensional harmonic oscillator with displacements in the \(x\) - and \(y\) -directions, the force constants being the same for each direction (the two bending modes of \(\mathrm{CO}_{2}\) is an example ). Show that the state resulting from the excitation of the oscillator to its first excited state can be regarded as possessing one unit of angular momentum about the \(z\) -axis. Hint. Show that \(\psi(x) \psi(y) \propto \mathrm{e}^{\mathrm{jp}}\)

The \(J+1 \leftarrow J\) rotational transitions of \(^{16} \mathrm{O}^{12} \mathrm{C}^{32} \mathrm{S}\) and \(^{16} \mathrm{O}^{12} \mathrm{C}^{34} \mathrm{S}\) occur at the following frequencies \((v / \mathrm{GHz})\) $$\begin{array}{lllll} \hline J & 1 & 2 & 3 & 4 \\ \hline^{16} \mathrm{O}^{12} \mathrm{C}^{32} \mathrm{S} & 24.32592 & 36.48882 & 48.65164 & 60.81408 \\ ^{16} \mathrm{O}^{12} \mathrm{C}^{34} \mathrm{S} & 23.73223 & & 47.46240 & \\ \hline \end{array}$$ Find (a) the rotational constants, (b) the moments of inertia, and (c) the CS and CO bond lengths. Hint. Begin by finding expressions for the moment of inertia \(I\) through \(I=m_{\Lambda} R_{A}^{2}+m_{B} R_{B}^{2}+m_{C} R_{C}^{2},\) where \(R_{X}\) is the distance of atom \(\mathrm{X}\) from the centre of mass. The easiest procedure is to use the result established in Exercise \(10.6,\) which leads to \(I=\left(m_{\mathrm{A}} m_{\mathrm{C}} / m\right)\left(R_{\mathrm{AB}}+R_{\mathrm{BC}}\right)^{2}+\left(m_{\mathrm{B}} / m\right)\left(m_{\mathrm{A}} R_{\mathrm{AB}}^{2}+m_{\mathrm{C}} R_{\mathrm{BC}}^{2}\right)\) The lengths \(R_{\text {AB }}\) and \(R_{\mathrm{BC}}\) may be found only if two values of \(I\) are known. Assume the bond lengths are the same in isotopomeric molecules.

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