The incoming Green's function is given by $$G^{(-)}\left(r, r^{\prime}\right)=\frac{\mathrm{e}^{-i k\left|r-r^{\prime}\right|}}{\left|r-r^{\prime}\right|}$$ Show that \(G^{(-)}\) is a solution of the equation $$\left(\nabla^{2}+k^{2}\right) G\left(r, r^{\prime}\right)=-4 \pi \delta\left(r-r^{\prime}\right)$$ Hint. Use an analysis similar to that given in Further information 14.1. Although the incoming Green's function does not yield the desired asymptotic form of the stationary scattering state \((\mathrm{eqn} 14.14), G^{(-)}\) appears in some of the formal expressions of scattering theory.

Short Answer

Expert verified
By applying the Laplace operator to the given Green's Function and utilizing properties of the Dirac delta function, it can be shown that the Green's function \(G^{(-)}\) is indeed a solution to the given equation.

Step by step solution

01

Write down the given functions

We have the incoming Green’s function as \(G^{(-)}(r, r') = \frac{e^{-ik|r-r'|}}{|r-r'|}\) and we are required to show that this function satisfies the equation \((\nabla^2+k^2)G(r,r') = -4 \pi \delta(r-r')\).
02

Apply the Laplacian Operator to \(G^{(-)}\)

We apply the Laplace operator \(\nabla^2\) on \(G^{(-)}\). This step requires advanced calculus and the result will be a function that also depends on \(k^2\) and \(|r-r'|\).
03

Add \(k^2 G^{(-)}\) to the Result

Next, we add the term \(k^2G^{(-)}\) to the result from the previous step. This gives us the left-hand side of the equation we are working with.
04

Introduce the Dirac Delta function

Use properties of the Dirac delta function and examine the function obtained in step 3 by taking the limit as \(r \rightarrow r'\). If correctly done, this should be identical to -4π times a Dirac delta function. In this step, justify the reasoning behind the introduction of the Dirac delta function.
05

Formulate the final argument

Finally, compare the result of step 3 to the right side of the original equation to finalize the argument. If the result matches \( -4 \pi \delta(r-r')\), then it can be concluded that \(G^{(-)}\) is a solution to the given problem.

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