Calculate the values of the following matrix elements between p-orbitals: (a) \(\left\langle\mathrm{p}_{x}\left|l_{z}\right| \mathrm{p}_{y}\right\rangle,\) (b) \(\left\langle\mathrm{p}_{x}\left|l_{+}\right| \mathrm{p}_{y}\right\rangle\) \((\mathrm{c})\left\langle\mathrm{p}_{z}\left|l_{y}\right| \mathrm{p}_{x}\right\rangle\) \((d)\left\langle p_{z}\left|l_{x}\right| p_{y}\right\rangle,\) and (e) \(\left\langle\mathrm{p}_{z}\left|l_{x}\right| \mathrm{p}_{x}\right\rangle .\) Hint. Use the relations between \(\mathrm{p}_{x}, \mathrm{p}_{y}, \mathrm{p}_{z}\) and \(\mathrm{p}_{0}, \mathrm{p}_{+1}, \mathrm{p}_{-1}\).

Short Answer

Expert verified
The matrix elements are: (a) The element \( \langle p_x | l_z | p_y \rangle \) is equal to iħ. (b) The element \( \langle p_x | l_+ | p_y \rangle \) is zero. (c) The element \( \langle p_z | l_y | p_x \rangle \) is zero. (d) The element \( \langle p_z | l_x | p_y \rangle \) is zero. (e) The element \( \langle p_z | l_x | p_x \rangle \) is also zero.

Step by step solution

01

Conversion Between Representations

Convert the x, y, and z representations of the p-orbitals into 0, +1, and -1 representations respectively. This can be done using the relations:\(p_{0}=\frac{1}{\sqrt{2}}(p_{x}-i p_{y})\), \(p_{+1}=p_{z}\), \(p_{-1}=\frac{1}{\sqrt{2}}(p_{x}+i p_{y})\)
02

Substituting the Converted Representations

Substitute the relations from Step 1 into the matrix elements to convert them into a form which can be solved using the commutation relations.
03

Applying Commutation Relations

Use the commutation properties of the angular momentum operators to calculate the matrix elements. The commutation relations are \( [l_{x},l_{y}]=i \hbar l_{z} \), \( [l_{y},l_{z}]=i \hbar l_{x} \), and \( [l_{z},l_{x}]=i \hbar l_{y} \). Also, use the relation \( l_{\pm} = l_x \pm il_y \). Calculate the different elements (a-e) separatedly.
04

Simplify Results

Simplify the results. Any orbital elements in which the initial and final state are not the same (for example \( |\langle p_x | l_z | p_y \rangle |\)) will be zero, due to the orthogonality of the p-orbitals.

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