In which case does the reaction go farthest to completion : \(K=1 ; K=10^{10} ; K=10^{-10}\) and why?

Short Answer

Expert verified
The reaction with K=10^{10} goes farthest to completion because a larger equilibrium constant indicates a greater proportion of products at equilibrium.

Step by step solution

01

Understanding the Equilibrium Constant (K)

The equilibrium constant (K) of a reaction gives the ratio of product concentrations to reactant concentrations at equilibrium. A larger K value indicates that the products are favored at equilibrium, while a smaller K value indicates that the reactants are favored.
02

Comparing Given K Values

We have three K values given: K=1, K=10^{10}, and K=10^{-10}. A K value of 1 indicates that the products and reactants are present in equal amounts at equilibrium. A K value of 10^{10} suggests a strong tendency for the reaction to produce products as it lies far to the right. A K value of 10^{-10} implies a strong tendency for the reaction to favor reactants, therefore it lies far to the left.
03

Determining the Extent of Reaction Completion

The farther the reaction goes to completion, the more products are formed at equilibrium. Since K=10^{10} is the largest of the three K values, it indicates that almost all reactants are converted into products. Therefore, the reaction with K=10^{10} goes farthest to completion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Constant
The equilibrium constant (K) is a pivotal concept in understanding chemical equilibria. It quantifies the balance between products and reactants in a chemical reaction at a given temperature. Defined by the law of mass action, the constant reflects the ratio of the concentrations of products raised to the power of their respective coefficients to the concentrations of reactants raised to the power of their coefficients in a balanced chemical equation.

When dealing with an equilibrium constant, there are a few key points to remember:
  • A larger K value (much greater than 1) suggests that, at equilibrium, the reaction heavily favors the formation of products.
  • A smaller K value (much less than 1) indicates that the reactants are preferred, with fewer products present at equilibrium.
  • A K value around 1 implies a relatively balanced amount of products and reactants at equilibrium.
In practice, knowing the K value helps predict whether the reactants or products are more dominant at equilibrium and can guide chemists in optimizing reactions for desired outcomes. It is, however, important to note that K does not provide information about the rate of the reaction or how quickly equilibrium is reached.
Reaction Completion
The extent of reaction completion is a measure of how far a reaction has progressed towards forming its products. When we speak about a reaction 'going to completion', we mean that nearly all the reactants have been converted into products. This extent can be influenced by various factors such as temperature, pressure, and concentration of reactants.

In the context of equilibrium constants:
  • A very high K value indicates that a reaction will go significantly towards completion.
  • A K value close to zero implies that the reaction will barely proceed before reaching equilibrium.
This aspect of chemical reactions is essential for applications where maximizing product yield is critical, such as in industrial chemical synthesis or pharmaceutical drug production.
Product and Reactant Concentrations
The concentrations of products and reactants at equilibrium are at the heart of what defines an equilibrium state. These concentrations do not change over time as long as the external conditions, such as temperature and pressure, remain constant. However, this does not imply that the chemical reaction has stopped. Rather, the rate at which the reactants form products is equal to the rate at which the products decompose back into reactants.

It is the equilibrium constant that offers a snapshot of this dynamic balance, and understanding how to calculate and interpret these concentrations can be crucial for anyone studying or working in the field of chemistry. For a given reaction at equilibrium, adjusting the concentration of one reactant or product can shift the position of equilibrium, a principle known as Le Chatelier's Principle.
Equilibrium in Chemical Reactions
Equilibrium is a fundamental concept in chemical reactions, referring to the state where the forward and reverse reactions occur at the same rate. It's important to recognize that equilibrium does not mean the reactants and products are present in equal amounts; it simply indicates that their concentrations have stabilized in a particular ratio that does not change over time. Some key pointers include:
  • Equilibrium can be reached regardless of whether the reaction starts with all reactants or all products, reflecting the dynamic nature of chemical processes.
  • Changes in conditions, like temperature or pressure, can 'shift' the equilibrium position, affecting the concentrations of reactants and products according to Le Chatelier's Principle.
  • The concept of equilibrium is widely applicable across different chemical contexts, from simple inorganic reactions in solution to complex biological systems like enzyme-substrate interactions.
Understanding equilibrium allows chemists to predict the results of reactions and manipulate conditions to favor the production of desired products.

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Most popular questions from this chapter

A compound formed by elements \(A\) and \(B\) crystallizes in cubic structure where \(A\) atoms are at the corners of a cube and \(B\) atoms are at the face centre. What is the formula of the compound?

\(\Delta G^{\circ}\) for \(\frac{1}{2} \mathrm{~N}_{2}+\frac{3}{2} \mathrm{H}_{2} \rightleftharpoons \mathrm{NH}_{3}\) is \(-16.5 \mathrm{~kJ} \mathrm{~mol}^{-1}\) at \(25^{\circ} \mathrm{C}\). Find out \(K_{\mathrm{p}}\) for the reaction. Also report \(K_{\mathrm{p}}\) and \(\Delta G^{\circ}\) for: $$ \mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3} \quad \text { at } 25^{\circ} \mathrm{C} $$

For the reaction; \(\mathrm{N}_{2 \mathrm{k} \mathrm{g}}+3 \mathrm{H}_{2(\mathrm{~g})} \rightleftharpoons 2 \mathrm{NH}_{3(\mathrm{~g})}\) At \(400 \mathrm{~K}, K_{\mathrm{p}}=41 \mathrm{~atm}^{-2}\). Find the value of \(K_{\mathrm{p}}\) for each of the following reactions at the same temperature: (i) \(2 \mathrm{NH}_{3(\mathrm{~g})} \Longrightarrow \mathrm{N}_{2(\mathrm{~g})}+3 \mathrm{H}_{2(\mathrm{~g})}\) (ii) \({ }_{2} \mathrm{~N}_{2(\mathrm{~g})}+\frac{3}{2} \mathrm{H}_{2(g)} \Longrightarrow \mathrm{NH}_{3(\mathrm{~g})}\); (iii) \(2 \mathrm{~N}_{2(\mathrm{~g})}+6 \mathrm{H}_{2(\mathrm{~g})} \rightleftharpoons 4 \mathrm{NH}_{3(\mathrm{~g})}\)

The first order diffraction of \(X\) -rays from a certain set of crystal planes oceurs at an angle of \(11.8^{\circ}\) from the planes. If the planes are \(0.281 \mathrm{~nm}\) apart, what is the wavelength of \(X\) -rays?

The equilibrium constant of the reaction; \(\mathrm{SO}_{3(\mathrm{~g})} \rightleftharpoons \mathrm{SO}_{2(\mathrm{~g})}+1 / 2 \mathrm{O}_{2(\mathrm{~g})}\); is \(0.20 \mathrm{~mole}^{1 / 2}\) litre \(^{-1 / 2}\) at \(1000 \mathrm{~K}\). Calculate equilibrium constant for $$ 2 \mathrm{SO}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}=2 \mathrm{SO}_{3(\mathrm{~g})} $$

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