Nitric oxide reacts with bromine and gives nitrosyl-bromide as per reaction given below: $$ 2 \mathrm{NO}_{(\mathrm{g})}+\mathrm{Br}_{2(\mathrm{~g})} \rightleftharpoons 2 \mathrm{NOBr}_{(\mathrm{g})} $$ When \(0.087\) mole of \(\mathrm{NO}\) and \(0.0437\) mole of \(\mathrm{Br}_{2}\) are mixed is a closed container at constant temperature, \(0.0518\) mole of NOBr is obtained at equilibrium. Calculate equilibrium amount of nitric oxide and bromine.

Short Answer

Expert verified
At equilibrium, there are 0.0611 moles of NO and 0.0178 moles of Br2 left.

Step by step solution

01

Write down the balanced chemical reaction

First, interpret the given chemical equation for the reaction: \[2 \mathrm{NO}_{(g)} + \mathrm{Br}_{2(g)} \rightleftharpoons 2 \mathrm{NOBr}_{(g)}\]. This reaction indicates that 2 moles of nitric oxide react with 1 mole of bromine to produce 2 moles of nitrosyl-bromide.
02

Determine the initial moles of reactants

According to the problem, initially there are 0.087 moles of NO and 0.0437 moles of Br2 present before the reaction reaches equilibrium.
03

Calculate the change in moles at equilibrium

To find the equilibrium amount of nitric oxide and bromine, use the fact that 0.0518 moles of NOBr are produced at equilibrium. From the stoichiometry of the balanced equation, 2 moles of NO produce 2 moles of NOBr, so the moles of NO that reacted is half the moles of NOBr formed. Moles of NO reacted = 0.0518 / 2 = 0.0259 moles. Since 1 mole of Br2 produces 2 moles of NOBr, the moles of Br2 that reacted is also 0.0259 moles.
04

Calculate the moles of reactants left at equilibrium

Subtract the number of moles that reacted from the initial number of moles to find the equilibrium amounts of the reactants. Moles of NO left at equilibrium = 0.087 - 0.0259 = 0.0611 moles. Moles of Br2 left at equilibrium = 0.0437 - 0.0259 = 0.0178 moles.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equilibrium
Understanding chemical equilibrium is pivotal for interpreting how chemical reactions occur in closed systems. At equilibrium, a chemical system has reached a state where the rate of the forward reaction equals the rate of the reverse reaction, resulting in no net change in the concentration of reactants and products over time. However, this does not mean that the amounts of reactants and products are equal, but rather that their concentrations have stabilized to constant values.

When calculating equilibrium conditions, as in the exercise with nitric oxide and bromine, we examine the amounts of reactants and products that are present once the system has reached this state. These calculations often involve applying the stoichiometry of the reaction to relate the changes in reactants to the changes in products. It is a construct that allows chemists to predict the concentrations of various species within a reaction mixture after given amounts of reactants are mixed.
Stoichiometry
Stoichiometry is the branch of chemistry that deals with the quantitative relationships between the reactants and products in a chemical reaction. The exercise provided illustrates how stoichiometry is used to determine the amounts of nitric oxide and bromine at equilibrium. We use the balanced chemical equation to understand how the reactants combine and form products.

The equation indicates that two moles of NO react with one mole of Br2 to produce two moles of NOBr. This is known as the mole ratio and is crucial for stoichiometric calculations. When we know the amount of one substance that reacts or is produced, we can use these mole ratios to calculate the corresponding amounts of the other substances involved in the reaction. Short, stoichiometry serves as the recipe for conducting and understanding the quantitative aspects of chemical reactions.
Chemical Reaction
A chemical reaction is a process that leads to the chemical transformation of one set of chemical substances to another. Chemical reactions are represented by chemical equations, like the one in our exercise: 2 NO(g) + Br2(g) ⇌ 2 NOBr(g). Such equations show the reactants (NO and Br2) on the left side and the products (NOBr) on the right, depicting the rearrangement of atoms during the reaction.

Understanding chemical reactions involves appreciating that atoms and molecules interact in specific ways to form new compounds, often releasing or absorbing energy in the process. In the context of our example, nitric oxide and bromine react to form nitrosyl bromide, following conservation of mass and consistent with the principles of stoichiometry.
Mole Concept
The mole concept is a method within chemistry for quantifying atoms, molecules, or other chemical entities. One mole is defined as exactly 6.022 x 1023 (Avogadro's number) of chemical units, be they atoms, molecules, electrons, or other particles. In the example provided, moles provide a way to quantify how much of each reactant we have and how much product is produced.

0.087 moles of NO and 0.0437 moles of Br2 initially are mixed. During the reaction to equilibrium, they yield 0.0518 moles of NOBr. Using the mole concept allows us to translate this information into concrete amounts of reactants that have reacted and to calculate how much remains unreacted at equilibrium, providing insight into the extent of the reaction and the composition of the final mixture.

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