Sodium metal crystallizes in a body centred cubic lattice with the cell edge \(a=4.29 \AA\). What is the radius of sodium atom?

Short Answer

Expert verified
The radius of the sodium atom is approximately 1.859 \(\AA\).

Step by step solution

01

Understanding Body-Centered Cubic (BCC) Lattice

In a body-centered cubic lattice, there are atoms at each corner of the cube and one atom in the center of the cube. The relation between the edge of the cube, 'a', and the radius of the atom, 'r', is given by the formula for the body diagonal: \(a\sqrt{3} = 4r\).
02

Expressing the Radius in Terms of the Cube Edge

Rearrange the formula to solve for the radius 'r': \(r = \frac{a\sqrt{3}}{4}\).
03

Calculating the Radius of Sodium Atom

Substitute the given edge length, 'a' = 4.29 angstroms (\(\AA\)), into the rearranged formula to find the radius 'r': \(r = \frac{4.29 \AA \times \sqrt{3}}{4}\). Calculate the value to get the radius of the sodium atom.
04

Perform the Calculation

After substituting the values: \(r = \frac{4.29 \times 1.732}{4}\), which is approximately \(r = \frac{7.43588}{4}\). Now, perform the division to find the value of 'r'.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lattice Structures in Solids
In the realm of material science and solid-state physics, understanding lattice structures in solids is indispensable. These lattice structures are essentially three-dimensional arrangements of atoms, ions, or molecules in a crystal. The most common lattice structures include simple cubic, face-centered cubic, and body-centered cubic (BCC), each with its unique geometrical arrangement and coordination number, which refers to the number of nearest neighbors an atom has.

Body-centered cubic lattice, in particular, is characterized by an atom at each of the eight corners of a cube and one atom at the very center of the cube. This configuration has an important implication for the material's properties, including its density and how it interacts with light or electricity. BCC structures are prevalent in metals like iron at certain temperatures, and as we explore further, in elements like sodium. Such knowledge not only helps in identifying materials with desired properties but also in manipulating these properties for various applications.
Crystallography in Physical Chemistry
The study of crystal structures and their properties falls under crystallography in physical chemistry. This branch of science is crucial as it allows scientists to visualize and understand the intricate arrangements of atoms within a solid. The discipline involves techniques like X-ray diffraction, which can be used to infer distances between layers of atoms and even measure the size of atoms or ions in a lattice.

This information is critical; for example, in pharmaceuticals, understanding the crystal structure of a drug can influence its efficacy and solubility. In materials science, the strength, reactivity, and other physical characteristics are often related to the arrangement of atoms in a lattice. By studying these arrangements in depth, chemists and material scientists can predict and explain the behaviors of materials under various conditions, leading to innovations in technology and industry.
Radius of an Atom Calculation
Calculating the radius of an atom within a solid matrix is a fundamental task in crystallography and materials science. The radius can be inferred from the lattice parameters, which define the dimensions of the unit cell—the smallest repeating unit of the lattice. In a body-centered cubic lattice, the atom's radius is intertwined with the cube's edge length. Given the cube edge, 'a', and the lattice structure, you can employ geometric relationships to determine the atomic radius.

For BCC lattices, the body diagonal—that is, a line drawn from one corner of the cube to the opposite corner passing through the center—will be four times the atomic radius in length. The formula derived from this relationship is essential as it provides insights into the space occupied by atoms in a solid. Understanding these dimensions allows for the prediction of various physical properties, such as density and thermal expansion, all of which are crucial for material selection in engineering applications.

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Most popular questions from this chapter

Calculate the number \((n)\) of atoms contained within (a) cubic cell, (b) a body centred cubic cell, (c) a face centred cubic cell.

Calculate the concentration of \(\mathrm{CO}_{2}\) in a soft drink bottle after the bottle is opened and sits at \(25^{\circ} \mathrm{C}\) under a \(\mathrm{CO}_{2}\) partial pressure of \(3.0 \times 10^{-4} \mathrm{~atm}\). Henry's law constant for \(\mathrm{CO}_{2}\) in water is \(3.1 \times 10^{-2}\) mol/litre-atm at this temperature.

Write euilibrium constant for the each : (a) \(\quad \mathrm{N}_{2} \mathrm{O}_{4(\mathrm{~g})} \rightleftharpoons 2 \mathrm{NO}_{2(\mathrm{~g})}\) (b) \(\quad \mathrm{KClO}_{3(\mathrm{~s})} \rightleftharpoons \mathrm{KCl}_{(\mathrm{s})}+(3 / 2) \mathrm{O}_{2(\mathrm{~g})}\) (c) \(\mathrm{CaC}_{2(\mathrm{~s})}+5 \mathrm{O}_{2(\mathrm{~g})} \rightleftharpoons 2 \mathrm{CaCO}_{3(\mathrm{~s})}+2 \mathrm{CO}_{2(\mathrm{~g})}\) (d) \(\mathrm{N}_{2(\mathrm{~g})}+3 \mathrm{H}_{2(\mathrm{~g})} \rightleftharpoons 2 \mathrm{NH}_{3(\mathrm{~g})}\) (e)Fe \(^{3+}{ }_{\text {(aq })}+\mathrm{SCN}_{\text {(aq.) }}^{*}=\mathrm{Fe}(\mathrm{SCN})^{2+}{ }_{\text {(aq })}\) (f) \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}_{(\mathrm{s})} \rightleftharpoons \mathrm{CuSO}_{4(\mathrm{~s})}+5 \mathrm{H}_{2} \mathrm{O}_{(\mathrm{v})}\)

The first order diffraction of \(X\) -rays from a certain set of crystal planes oceurs at an angle of \(11.8^{\circ}\) from the planes. If the planes are \(0.281 \mathrm{~nm}\) apart, what is the wavelength of \(X\) -rays?

The ester, ethyl acetate is formed by the reaction between ethanol and acetic acid and equilibrium is represented as : \(\mathrm{CH}_{3} \mathrm{COOH}_{(\mathrm{l})}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}_{(\mathrm{l})} \rightleftharpoons \mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H}_{5(\mathrm{aq})}+\mathrm{H}_{2} \mathrm{O}_{(\mathrm{l})}\) (a) Write the concentration ratio (reaction quotient), \(Q_{\mathrm{e}}\), for this reaction. Note that water is not in excess and is not a solvent in this reaction. (b) At \(293 \mathrm{~K}\), if one starts with \(1.00\) mole of acetic acid and \(0.180\) of ethanol, there is \(0.171\) mole of ethyl acetate in the final equilibrium mixture. Calculate the equilibrium constant. (c) Starting with \(0.500\) mole of ethanol and \(1.000\) mole of acetic acid and maintaining it at \(293 \mathrm{~K}, 0.214\) mole of ethyl acetate is found after some time. Has equilibrium been reached?

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