The \(K_{\mathrm{w}}\) for \(2 \mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{H}_{3} \mathrm{O}^{+}+\mathrm{OH}^{-}\) changes from \(10^{-14}\) at \(25^{\circ} \mathrm{C}\) to \(9.62 \times 10^{-14}\) at \(60^{\circ} \mathrm{C} .\) What is \(\mathrm{pH}\) of water at \(60^{\circ} \mathrm{C} ?\) What happens to its neutrality?

Short Answer

Expert verified
The \(\text{pH}\) of water at \(60^\circ \mathrm{C}\) is calculated as \(-\log(9.8 \times 10^{-7})\), which is approximately 6.01. At \(60^\circ \mathrm{C}\), even with equal concentrations of \(\mathrm{H}_3\mathrm{O}^+\) and \(\mathrm{OH}^-\), water is not neutral as the pH is less than 7.

Step by step solution

01

Understanding Water's Ion Product at 60°C

The ion product constant of water, denoted as \(K_\mathrm{w}\), is the product of the concentrations of the hydronium \(\mathrm{H}_3\mathrm{O}^+\) and hydroxide \(\mathrm{OH}^-\) ions in water. At 60°C, \(K_\mathrm{w}\) is given as \(9.62 \times 10^{-14}\).
02

Calculate the Concentrations of H₃O⁺ and OH⁻

Since the water is neutral at 25°C, the concentrations of hydronium and hydroxide ions are equal. Therefore, at 60°C, we assume the concentrations of \(\mathrm{H}_3\mathrm{O}^+\) and \(\mathrm{OH}^-\) are still equal, which we denote as \(x\). So, we can write the equilibrium expression as \(K_\mathrm{w} = x^2\). Solving for \(x\), we get \(x = \sqrt{K_\mathrm{w}} = \sqrt{9.62 \times 10^{-14}}\).
03

Calculate the Hydronium Ion Concentration

Take the square root of \(K_\mathrm{w}\) to find the concentration of \(\mathrm{H}_3\mathrm{O}^+\), which is \(x = \sqrt{9.62 \times 10^{-14}} = 9.8 \times 10^{-7} \mathrm{M}\).
04

Calculate the pH

The pH is the negative logarithm (base 10) of the concentration of \(\mathrm{H}_3\mathrm{O}^+\). Plug in the concentration of hydronium ions to get \(\text{pH} = -\log(9.8 \times 10^{-7})\).
05

Assess the Neutrality of Water at 60°C

Water is neutral when the pH is 7 at 25°C, which corresponds to the equal concentrations of hydronium and hydroxide ions. At 60°C, even though the concentrations of hydronium and hydroxide ions are still equal, the pH will not be 7 due to the change in \(K_\mathrm{w}\), indicating water is no longer neutral.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Water's Ion Product (Kw)
The ion product of water, denoted as Kw, is essential in understanding the self-ionization of water. This constant represents the product of the molar concentrations of hydronium ions (H3O+) and hydroxide ions (OH-) in water. At 25°C, the value for Kw is well-known to be 10-14. However, as temperature increases, so does the ion product. For instance, at 60°C, Kw becomes 9.62 x 10-14. This increase suggests that water is more dissociated into its ions at higher temperatures, compared to room temperature.

In practical terms, knowing Kw at a specific temperature allows us to calculate the concentrations of hydronium and hydroxide ions in pure water, which is crucial for understanding pH and the acidic or basic nature of aqueous solutions at that temperature.
Hydronium Ion Concentration (H3O+)
When water molecules split into ions, we see the emergence of hydronium ions, written as H3O+. The concentration of these ions in water essentially determines the acidity of the solution. A high concentration implies a low pH, indicating an acidic solution, while a low concentration corresponds to a high pH, indicating a basic solution.

At different temperatures, H3O+ concentration varies because the Kw changes. By assuming the molar concentration of hydronium ions is equal to that of hydroxide ions in pure water at a new temperature (like 60°C), we can calculate it by taking the square root of the Kw. This calculation directly reflects the fact that, as temperature changes, so does the balance point at which water is neither acidic nor basic.
pH Calculation
pH is a measure of how acidic or basic water is, on a scale from 0 to 14, with 7 being neutral. It's defined as the negative logarithm of the hydronium ion concentration. To compute the pH of water or any aqueous solution, one essentially takes the negative base-10 logarithm of the H3O+ concentration. As seen in the aforementioned exercise, this yields the pH of water at 60°C when we plug in the computed concentration of hydronium ions.

This relationship implies that even a slight deviation in H3O+ concentration can result in a significant change in pH. Therefore, the pH calculation is a crucial tool for scientists and educators to indicate exactly how the acidity or basicity of water is affected by temperature.
Neutrality of Water
Water's neutrality is a concept that revolves around its pH level being at 7, which is considered neutral. This occurs when the concentrations of hydronium and hydroxide ions are perfectly balanced, which is indeed the case at 25°C for pure water, with a Kw at this temperature being exactly 10-14. However, this delicate balance gets disrupted as we change the temperature.

At higher temperatures like 60°C, the equilibrium shifts, leading to a change in the ion product of water. Consequently, even though the concentration of hydronium equals that of hydroxide ions, the pH deviates from 7, indicating that water is no longer neutral under these conditions. This reality is of particular importance in chemical reactions and processes where maintaining a strict pH is vital, such as in biological systems and industrial applications.

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