Chapter 12: Problem 19
$$ \begin{aligned} &\text { Calculate the value of } \Delta G \text { at } 700 \mathrm{~K} \text { for the reaction } n X \longrightarrow m B .^{-1}\\\ &\text { Given that value of } \Delta H=-113 \mathrm{~kJ} \mathrm{~mol}^{-1} \text { and } \Delta S=-145 \mathrm{JK} \mathrm{mol}^{-1} \text { . } \end{aligned} $$
Short Answer
Step by step solution
- Understand Gibbs Free Energy
- Convert Units for Consistency
- Convert Enthalpy
- Insert Values into Equation
- Perform the Calculation
- Final Calculation of Delta G
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Enthalpy Change (abla H)
For example, if a reaction releases heat to the surroundings, abla H is negative, as is the case in our exercise with a value of -113 kJ/mol. This indicates an exothermic reaction where energy is expelled into the environment. In practical terms, ensuring that abla H is consistently measured in Joules (J) or kilojoules (kJ) is crucial, as miscalculations can occur if unit conversions are not handled properly. Thus, converting the given enthalpy change from kJ to J is a necessary step to align with the standard SI unit of Joules for subsequent calculations.abla H and will significantly impact abla G, Gibbs Free Energy's computation, as seen later.
Entropy Change (abla S)
It is essential to keep entropy in units of J/(mol·K) when performing calculations involving temperature. As we see in the provided exercise, the entropy change is -145 J/K·mol, indicative of a decrease in system disorder during the reaction. This negative value plays a role in calculating Gibbs Free Energy and helps in understanding the feasibility of the chemical process from a thermodynamic standpoint.
Temperature in Thermodynamics
In calculations involving Gibbs Free Energy, it is vital that temperature is used correctly in Kelvin units to ensure that the entropy's contribution to abla G is accurately determined. For instance, in our exercise example, the temperature is given at 700 K, which is central to evaluating the reaction's spontaneous nature at this specific state. Its interplay with abla S provides insight into the thermal energy available to increase disorder within the system.
Gibbs Free Energy Equation
If abla G is negative, the reaction is spontaneous, meaning it can occur without external input. A positive abla G implies that the reaction is non-spontaneous under given conditions, and zero abla G indicates a system in equilibrium, where the reaction proceeds in neither direction spontaneously. It is crucial to execute careful unit conversions to ensure accuracy, as we saw in the exercise, converting every parameter to Joules before substituting them into the equation ensures coherence in the calculated value of abla G. Once calculated, the result then often gets converted back to kJ or other units as required for reporting or comparison with standard values.