The heat of solution of \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) in water was determined by measuring the amount of electrical work needed to compensate for the cooling which would otherwise óccur when the salt dissolves. After the \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) was added to the water, electrical energy was provided by passage of current through a resistance coil until the temperature of the solution reached the value it had prior to the addition of salt. In a typical experiment, \(4.4 \mathrm{~g}\) of \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) was added to \(200 \mathrm{~g}\) water. A current of \(0.75\) ampere was provided through the heater coil, and the voltage across the terminals was \(6.0 \mathrm{~V}\). The current was applied for \(5.2\) minute. Calculate \(\Delta H\) for the solution of \(1.0\) mole \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) in enough water to give same concentration as was attained in the above experiment.

Short Answer

Expert verified
First, calculate the energy in joules using the given current, voltage, and time; then, determine the moles of NH4NO3 and use these values to calculate the enthalpy change per mole. Scale up the calculated ∆H to the amount of energy it would take for 1 mole, ensuring the concentration remains the same.

Step by step solution

01

- Calculate the electrical energy transferred

Determine the total amount of electrical energy used to heat the solution back to its original temperature. Use the formula: Energy (in joules) = Power (in watts) * Time (in seconds), where Power = Current (in amperes) * Voltage (in volts).
02

- Convert the time from minutes to seconds

Since power is typically measured in watts and time in seconds, convert the time from minutes to seconds to use in the formula by multiplying by 60. Thus, time = 5.2 minutes * 60 seconds/minute.
03

- Calculate the moles of NH4NO3

To relate the energy to the enthalpy change per mole, calculate the number of moles of (NH_4)(NO_3) used in the experiment by using its molar mass: Moles of NH4NO3 = mass (in g) / molar mass (in g/mol).
04

- Calculate the enthalpy change per mole

Use the total energy from Step 1 and the moles of NH4NO3 from Step 3 to calculate the enthalpy change per mole, which is ∆H (in J/mol). ∆H for the given mass is the energy divided by the number of moles.
05

- Scaling up to 1 mole

To find ∆H for the solution of 1 mole NH4NO3, make sure that the concentration of the solution is the same. Calculate the enthalpy change for 1 mole based on the enthalpy change per mole found in the experiment.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat of Solution
Heat of solution, in thermodynamics, refers to the total amount of heat energy that is either absorbed or released when a substance, such as a salt, is dissolved in a solvent like water. This process is crucial because it tells us whether the dissolving process is endothermic (absorbing heat) or exothermic (releasing heat). In the given exercise, the dissolution of ammonium nitrate (\( \text{NH}_4\text{NO}_3 \)) in water is endothermic; the solution gets cooler, which implies that it absorbs heat from the surroundings.

To counter this cooling effect and obtain a precise measurement of the heat of solution, electrical energy is used to heat the solution back up to its original temperature. This method ensures that the amount of heat absorbed by the solution is equal to the electrical energy supplied, allowing for an accurate calculation of the enthalpy change. The heat of solution for a particular substance can greatly influence practical applications, such as in pharmacology, where it can affect drug formulation and delivery.
Molar Mass
Molar mass is a fundamental concept in chemistry that represents the mass of one mole of a substance, typically expressed in grams per mole (g/mol). It is a critical factor in converting between the mass of a substance and the number of moles. For substances like \(\text{NH}_4\text{NO}_3 \), knowledge of molar mass allows chemists to determine how many moles are present in a certain mass of the substance.

In the context of our exercise, the student must first ascertain the molar mass of ammonium nitrate, which can be derived from the periodic table as the sum of the atomic masses of the constituent nitrogen, hydrogen, and oxygen atoms. Once the molar mass is known, the student is equipped to convert the mass of \(\text{NH}_4\text{NO}_3 \) used in the experiment to moles, which is a crucial step for the calculation of enthalpy change.
Electrical Energy
Electrical energy is a form of energy resulting from the flow of electric charge through a conductor. It's commonly used to perform work, such as heating an element in a resistive heater. This energy can be calculated by multiplying the power consumed (in watts) by the time (in seconds) during which the power is applied. Power itself is the product of the current (in amperes) and the potential difference (in volts).

In our exercise, the electrical energy was provided by passing a current through a resistance coil, supplying the necessary heat to maintain the solution's temperature. The accurate measurement of electrical energy applied is essential for determining the heat of solution of \(\text{NH}_4\text{NO}_3 \) when dissolved in water. Understanding the relationship between electrical energy and heat energy is not only important in chemistry but also in fields like physics and engineering where energy transformations are involved.
Enthalpy Change per Mole
Enthalpy change per mole is a thermodynamic concept that indicates the amount of heat absorbed or released during a reaction or a process such as dissolving, per mole of a substance. It's a key measurement in understanding the energy changes associated with chemical reactions and is calculated by dividing the total energy change by the number of moles of the reactant or product involved.

In the exercise we've discussed, to find the enthalpy change per mole for the dissolution of \(\text{NH}_4\text{NO}_3 \), you start with the total electrical energy supplied (calculated from the voltage, current, and time). Then, using the molar mass and the mass of the salt used, you calculate the moles of \(\text{NH}_4\text{NO}_3 \). Dividing the total energy applied by the number of moles gives us the enthalpy change per mole. This value is crucial as it provides a standard way to express and compare the energetic changes for chemical processes independent of the quantity of the substances used.

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Most popular questions from this chapter

The commercial production of water gas utilizes the reaction under standard conditions: \(\mathrm{C}+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightarrow \mathrm{H}_{2}+\mathrm{CO}\). The heat required for this endothermic reaction may be supplied by adding a limited amount of air and burning some carbon to \(\mathrm{CO}_{2}\). How many \(\mathrm{g}\) of carbon must be burnt to \(\mathrm{CO}_{2}\) to provide enough heat for the water gas conversion of \(100 \mathrm{~g}\) carbon? Neglect all heat losses to the environment. Also \(\Delta H_{\mathrm{f}}^{2}\) of \(\mathrm{CO}, \mathrm{H}_{2} \mathrm{O}_{(\mathrm{g})}\) and \(\mathrm{CO}_{2}\) are \(-110.53\), \(-241.81\) and \(-393.51 \mathrm{~kJ} / \mathrm{mol}\) respectively.

The integral enthalpy of solution in \(\mathrm{kJ}\) of one mole of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) dissolved in \(n\) mole of water is given by: $$ \Delta H_{s}=\frac{75.6 \times n}{n+1.8} $$ Calculate \(\Delta H\) for the following process: (a) 1 mole of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) dissolved in \(2 \mathrm{~mole}\) of \(\mathrm{H}_{2} \mathrm{O}\). (b) 1 mole of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) dissolved in 7 mole of \(\mathrm{H}_{2} \mathrm{O}\). (c) 1 mole of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) dissolved in 5 mole of \(\mathrm{H}_{2} \mathrm{O}\). (d) solution (a) dissolved in 5 mole of \(\mathrm{H}_{2} \mathrm{O}\). (e) 1 mole of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) dissolved in excess of \(\mathrm{H}_{2} \mathrm{O}\).

\(1.00\) litre sample of a mixture of \(\mathrm{CH}_{4(\mathrm{~g})}\) and \(\mathrm{O}_{2(\mathrm{~g})}\) measured at \(25^{\circ} \mathrm{C}\) and 740 torr was allowed to react at constant pressure in a calorimeter which together with its contents had a heat capacity of \(1260 \mathrm{cal} / \mathrm{K}\). The complete combustion of the methane to \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) caused a temperature rise in the calorimeter of \(0.667 \mathrm{~K}\). What was the mole per cent of \(\mathrm{CH}_{4}\) in the original mixture? \(\Delta H_{\text {comb }}^{\circ}\left(\mathrm{CH}_{4}\right)=-215 \mathrm{k}\) cal \(\mathrm{mol}^{-1}\).

\begin{aligned} &\text { The heat of dissociation of } \mathrm{H}_{2} \text { is } 435 \mathrm{~kJ} \mathrm{~mol}^{-1} \text { . If } \mathrm{C}_{(\mathrm{s})} \longrightarrow \mathrm{C}_{(\mathrm{g})} \text { ; }\\\ &\Delta H=720 \mathrm{~kJ} \mathrm{~mol}^{-1}, \text { calculate the bond energy per mol of the } \mathrm{C}-\mathrm{H} \text { bond }\\\ &\text { in } \mathrm{CH}_{4} \text { molecule. } \Delta H_{\mathrm{f}} \text { for } \mathrm{CH}_{4}=-75 \mathrm{~kJ} \mathrm{~mol}^{-1} \text { . } \end{aligned}

The standard enthalpy of formation of \(\mathrm{FeO}\) and \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) is \(-65 \mathrm{kcal}\) \(\mathrm{mol}^{-1}\) and \(-197\) kcal mol \(^{-1}\) respectively. A mixture of two oxides contains \(\mathrm{FeO}\) and \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) in the mole ratio \(2: 1 .\) If by oxidation, it is changed into a \(1: 2\) mole ratio mixture, how much of thermal energy will be released per mol of initial mixture.

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