The commercial production of water gas utilizes the reaction under standard conditions: \(\mathrm{C}+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightarrow \mathrm{H}_{2}+\mathrm{CO}\). The heat required for this endothermic reaction may be supplied by adding a limited amount of air and burning some carbon to \(\mathrm{CO}_{2}\). How many \(\mathrm{g}\) of carbon must be burnt to \(\mathrm{CO}_{2}\) to provide enough heat for the water gas conversion of \(100 \mathrm{~g}\) carbon? Neglect all heat losses to the environment. Also \(\Delta H_{\mathrm{f}}^{2}\) of \(\mathrm{CO}, \mathrm{H}_{2} \mathrm{O}_{(\mathrm{g})}\) and \(\mathrm{CO}_{2}\) are \(-110.53\), \(-241.81\) and \(-393.51 \mathrm{~kJ} / \mathrm{mol}\) respectively.

Short Answer

Expert verified
The mass of carbon that must be burnt to CO2 to supply enough heat for the conversion of 100 g of carbon to water gas is calculated by balancing the heat release from the combustion with the endothermic energy requirement of the reaction.

Step by step solution

01

Analyze the Energy Involved in the Reaction

First, calculate the energy change during the conversion of 100 g of carbon to water gas. Use the enthalpy of formation (ΔHf°) values for carbon monoxide (CO) and water vapor (H2O(g)), and assume 100 g of carbon is completely converted to these products.
02

Calculate Moles of Carbon

Determine the moles of carbon used in the conversion. The molar mass of carbon (C) is approximately 12.01 g/mol.
03

Calculate Enthalpy Change for Water Gas Conversion

Calculate the enthalpy changes for the formation of CO and H2 from C and H2O using the provided ΔHf values. Sum these to find the total enthalpy change for the conversion of carbon to water gas.
04

Calculate Heat Released by Burning Carbon to CO2

Calculate the amount of heat released by burning carbon to CO2 using the enthalpy of formation for CO2.
05

Determine Moles of Carbon Needed to Burn

Determine the moles of carbon needed to burn to CO2 to supply the heat for the water gas conversion, ensuring the heat provided equals the endothermic heat requirement.
06

Convert Moles of Carbon to Mass

Convert the calculated moles of carbon that need to be burned to mass in grams using the molar mass of carbon.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Enthalpy of Formation
Enthalpy of formation, represented as \( \Delta H_f^\circ \), is a fundamental concept in thermochemistry relating to the heat change associated with the formation of a compound from its elements in their standard states. In simpler terms, it measures the amount of energy absorbed or released when a compound is created from its elemental parts.

For instance, in the reaction \( \mathrm{C} + \mathrm{H_2O(g)} \rightarrow \mathrm{H_2} + \mathrm{CO} \), we must consider the enthalpy of formation for each product (carbon monoxide and hydrogen gas) and reactants. If the \( \Delta H_f^\circ \) values are negative, it implies that energy is released when a mole of the compound is formed under standard conditions. In our case, \( \Delta H_f^\circ \) for \( \mathrm{CO} \) and \( \mathrm{CO_2} \) is negative, indicating exothermic reactions.

When using \( \Delta H_f^\circ \) for calculations, it's important to remember that the values depend on the temperature and pressure being standard (298 K and 101.3 kPa). Students must also know how to use these values in conjunction with stoichiometry to accurately determine the heat changes in chemical reactions.
Stoichiometry
Stoichiometry is the field of chemistry that involves calculating the quantities of reactants and products in chemical reactions. It's essentially the math behind chemistry, allowing us to predict how much of each substance is involved in a reaction.

To solve stoichiometric problems, such as determining how many grams of carbon must be burned to supply enough heat for the water gas conversion, one must first convert mass to moles using the molar mass. The molar mass of carbon is \(12.01 \,\text{g/mol}\), and so for \(100 \,\text{g}\) of carbon, you divide by this value to find the moles of carbon involved.

Moles of Carbon for Water Gas Conversion

Using the equation \( \text{mass} = \text{moles} \times \text{molar mass} \), you reverse the process to convert moles back to grams when necessary. By understanding how to balance equations, students can use stoichiometry to ensure that mass and energy are conserved across the reaction and to calculate yields.
Thermochemistry
Thermochemistry is the study of heat changes that accompany chemical reactions and phase changes. Understanding how energy is transferred, either as heat or work, is essential in predicting the direction and extent of chemical reactions.

In the commercial production of water gas, thermochemistry helps us understand that heat must be continuously supplied for the endothermic reaction to proceed. The reaction requires the input of energy, which, in a practical industrial setting, is supplied by burning a portion of carbon to \( \mathrm{CO_2} \).

According to the law of conservation of energy, the heat released from burning carbon to \( \mathrm{CO_2} \) can be harnessed to fuel the endothermic water gas reaction. This is a clever use of thermochemistry to ensure that energy requirements are met without external energy inputs, hence optimizing the production process.
Chemical Reactions
Chemical reactions are processes where reactants transform into products through the making and breaking of chemical bonds. There are different types of reactions, including synthesis, decomposition, single replacement, double replacement, and combustion, each with unique characteristics.

The water gas conversion is a type of endothermic reaction, meaning it absorbs heat. For this reaction to occur, we need an additional exothermic process – the combustion of carbon to carbon dioxide – to supply the necessary heat. This illustrates the interplay of different chemical reaction types in industrial processes.

Conservation in Chemical Reactions

One must be mindful of conservation principles, such as the conservation of mass and energy. These principles dictate that in a closed system, mass and energy cannot be created or destroyed, only converted. In the example given, burning carbon to \( \mathrm{CO_2} \) conserves energy by channeling it into the generation of water gas, showcasing the practical application of these fundamental chemical principles in real-world scenarios.

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Most popular questions from this chapter

The heat of solution of \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) in water was determined by measuring the amount of electrical work needed to compensate for the cooling which would otherwise óccur when the salt dissolves. After the \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) was added to the water, electrical energy was provided by passage of current through a resistance coil until the temperature of the solution reached the value it had prior to the addition of salt. In a typical experiment, \(4.4 \mathrm{~g}\) of \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) was added to \(200 \mathrm{~g}\) water. A current of \(0.75\) ampere was provided through the heater coil, and the voltage across the terminals was \(6.0 \mathrm{~V}\). The current was applied for \(5.2\) minute. Calculate \(\Delta H\) for the solution of \(1.0\) mole \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) in enough water to give same concentration as was attained in the above experiment.

\begin{aligned} &\text { The heat of dissociation of } \mathrm{H}_{2} \text { is } 435 \mathrm{~kJ} \mathrm{~mol}^{-1} \text { . If } \mathrm{C}_{(\mathrm{s})} \longrightarrow \mathrm{C}_{(\mathrm{g})} \text { ; }\\\ &\Delta H=720 \mathrm{~kJ} \mathrm{~mol}^{-1}, \text { calculate the bond energy per mol of the } \mathrm{C}-\mathrm{H} \text { bond }\\\ &\text { in } \mathrm{CH}_{4} \text { molecule. } \Delta H_{\mathrm{f}} \text { for } \mathrm{CH}_{4}=-75 \mathrm{~kJ} \mathrm{~mol}^{-1} \text { . } \end{aligned}

The integral enthalpy of solution in \(\mathrm{kJ}\) of one mole of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) dissolved in \(n\) mole of water is given by: $$ \Delta H_{s}=\frac{75.6 \times n}{n+1.8} $$ Calculate \(\Delta H\) for the following process: (a) 1 mole of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) dissolved in \(2 \mathrm{~mole}\) of \(\mathrm{H}_{2} \mathrm{O}\). (b) 1 mole of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) dissolved in 7 mole of \(\mathrm{H}_{2} \mathrm{O}\). (c) 1 mole of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) dissolved in 5 mole of \(\mathrm{H}_{2} \mathrm{O}\). (d) solution (a) dissolved in 5 mole of \(\mathrm{H}_{2} \mathrm{O}\). (e) 1 mole of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) dissolved in excess of \(\mathrm{H}_{2} \mathrm{O}\).

The standard enthalpy of formation of \(\mathrm{FeO}\) and \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) is \(-65 \mathrm{kcal}\) \(\mathrm{mol}^{-1}\) and \(-197\) kcal mol \(^{-1}\) respectively. A mixture of two oxides contains \(\mathrm{FeO}\) and \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) in the mole ratio \(2: 1 .\) If by oxidation, it is changed into a \(1: 2\) mole ratio mixture, how much of thermal energy will be released per mol of initial mixture.

\(1.00\) litre sample of a mixture of \(\mathrm{CH}_{4(\mathrm{~g})}\) and \(\mathrm{O}_{2(\mathrm{~g})}\) measured at \(25^{\circ} \mathrm{C}\) and 740 torr was allowed to react at constant pressure in a calorimeter which together with its contents had a heat capacity of \(1260 \mathrm{cal} / \mathrm{K}\). The complete combustion of the methane to \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) caused a temperature rise in the calorimeter of \(0.667 \mathrm{~K}\). What was the mole per cent of \(\mathrm{CH}_{4}\) in the original mixture? \(\Delta H_{\text {comb }}^{\circ}\left(\mathrm{CH}_{4}\right)=-215 \mathrm{k}\) cal \(\mathrm{mol}^{-1}\).

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