Chapter 15: Problem 10
How much charge is required for the reduction of (a) 1 mole of \(\mathrm{Al}^{3+}\) to \(\mathrm{Al}\) (b) 1 mole of \(\mathrm{Cu}^{2+}\) to \(\mathrm{Cu}\) (c) 1 mole of \(\mathrm{MnO}_{4}^{4-}\) to \(\mathrm{Mn}^{2+}\) (d) 1 mole of \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}\) to \(\mathrm{Cr}^{3+}\)
Short Answer
Expert verified
The amount of charge required for the reduction of 1 mole of substances is: (a) 289,455 C, (b) 192,970 C, (c) 482,425 C, and (d) 1,157,820 C.
Step by step solution
01
Understanding the Faraday's Law of Electrolysis
Faraday's Law of Electrolysis states that the amount of a substance deposited or liberated at an electrode during electrolysis is directly proportional to the amount of charge passed through the electrolyte. The formula for calculating charge (Q) is: Q = n × F × z, where n is the amount of substance in moles, F is Faraday's constant (96,485 C/mol), and z is the number of moles of electrons required to reduce or oxidize 1 mole of the substance.
02
Calculating the Charge for the Reduction of \(\mathrm{Al}^{3+}\) to \(\mathrm{Al}\)
For every mole of \(\mathrm{Al}^{3+}\) ions, 3 moles of electrons are required to reduce it to aluminum metal. Using the formula Q = n × F × z, we calculate the charge: Q = 1 mole × 96,485 C/mol × 3 = 289,455 C.
03
Calculating the Charge for the Reduction of \(\mathrm{Cu}^{2+}\) to \(\mathrm{Cu}\)
The copper ion \(\mathrm{Cu}^{2+}\) requires 2 moles of electrons to reduce to copper metal. Thus, the charge required is Q = 1 mole × 96,485 C/mol × 2 = 192,970 C.
04
Calculating the Charge for the Reduction of \(\mathrm{MnO}_{4}^{4-}\) to \(\mathrm{Mn}^{2+}\)
To reduce \(\mathrm{MnO}_{4}^{4-}\) to \(\mathrm{Mn}^{2+}\), 5 moles of electrons are needed for each mole of \(\mathrm{MnO}_{4}^{4-}\). Therefore, the charge is Q = 1 mole × 96,485 C/mol × 5 = 482,425 C.
05
Calculating the Charge for the Reduction of \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}\) to \(\mathrm{Cr}^{3+}\)
For the reduction of \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}\) to \(\mathrm{Cr}^{3+}\), 6 moles of electrons are needed per \(\mathrm{Cr}^{3+}\). However, there are 2 chromium atoms in each dichromate ion. Thus, the total number of moles of electrons needed is 12. The charge required is Q = 1 mole × 96,485 C/mol × 12 = 1,157,820 C.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electrochemical Reduction
Electrochemical reduction is a fundamental process in electrochemistry where electrons are gained by atoms or molecules, typically occurring at the cathode in an electrochemical cell. It is essentially the reverse of oxidation, and these redox processes play a crucial role in various technologies, including batteries, corrosion, and industrial metal recovery. In the context of Faraday's Law of Electrolysis, electrochemical reduction relates to how ions in a solution are reduced to form a solid metal through the gain of electrons, quantified by the amount of electric charge passed through the solution.
For example, when a metal ion such as \(\mathrm{Al}^{3+}\) is reduced to aluminum metal (Al), it requires three electrons per ion. These electrons are provided by an external electrical source, and the number of electrons needed dictates the total charge required to achieve the reduction. Understanding the electrochemical reduction process is essential for accurately calculating this charge and developing applications ranging from metal plating to the synthesis of chemicals.
For example, when a metal ion such as \(\mathrm{Al}^{3+}\) is reduced to aluminum metal (Al), it requires three electrons per ion. These electrons are provided by an external electrical source, and the number of electrons needed dictates the total charge required to achieve the reduction. Understanding the electrochemical reduction process is essential for accurately calculating this charge and developing applications ranging from metal plating to the synthesis of chemicals.
Mole Concept
The mole concept is a central pillar of chemistry, providing a way to quantify the amount of substance involved in chemical reactions. A mole corresponds to Avogadro's number, approximately \(6.022 \times 10^{23}\) entities, whether they are atoms, ions, molecules, or electrons. This number is extremely useful when correlating the mass of a substance to its participatory role in a chemical process.
Applying the mole concept allows us to quantify the exact number of entities involved in redox reactions occurring during electrolysis. For instance, one mole of \(\mathrm{Cu}^{2+}\) ions requires two moles of electrons to complete the reduction to copper metal. The mole concept facilitates the translation of abstract charges and small particles into a more tangible form that can be measured, observed, and applied in stoichiometric calculations, bridging the gap between microscopic particles and macroscopic quantities.
Applying the mole concept allows us to quantify the exact number of entities involved in redox reactions occurring during electrolysis. For instance, one mole of \(\mathrm{Cu}^{2+}\) ions requires two moles of electrons to complete the reduction to copper metal. The mole concept facilitates the translation of abstract charges and small particles into a more tangible form that can be measured, observed, and applied in stoichiometric calculations, bridging the gap between microscopic particles and macroscopic quantities.
Calculation of Charge
The calculation of charge is a critical step in electrolysis and involves determining the total amount of electricity required to drive a chemical reaction. According to Faraday's Law, this charge (\(Q\)) is calculated using the formula \(Q = n \times F \times z\), where \(n\) is the number of moles of substance being reduced or oxidized, \(F\) is the Faraday's constant (\(96,485 \text{ C/mol}\)), and \(z\) is the valence number of ions, which denotes the number of electrons transferred per ion during the reaction.
For example, to find the charge required to reduce one mole of \(\mathrm{MnO}_{4}^{4-}\) to \(\mathrm{Mn}^{2+}\), we consider that five electrons are exchanged per \(\mathrm{MnO}_{4}^{4-}\) ion. Thus, the charge is the product of the number of moles, the constant \(F\), and the number of electrons exchanged. This systematic approach to calculating charge is critical for designing and operating electrochemical cells for applications such as metal electroplating and electrolytic production of chemicals.
For example, to find the charge required to reduce one mole of \(\mathrm{MnO}_{4}^{4-}\) to \(\mathrm{Mn}^{2+}\), we consider that five electrons are exchanged per \(\mathrm{MnO}_{4}^{4-}\) ion. Thus, the charge is the product of the number of moles, the constant \(F\), and the number of electrons exchanged. This systematic approach to calculating charge is critical for designing and operating electrochemical cells for applications such as metal electroplating and electrolytic production of chemicals.
Stoichiometry in Redox Reactions
Stoichiometry in redox reactions refers to the quantitative relationship between reactants and products. In the context of electrolysis, it is critical to understand stoichiometry to determine the amount of reactants required or products formed. These calculations consider the moles of electrons exchanged in reducing or oxidizing a substance as per the mole concept.
In a redox reaction, atoms change their oxidation states by losing or gaining electrons. The conservation of charge principle dictates that the number of electrons lost must equal the number of electrons gained. Applying this principle in stoichiometry involves using the balanced chemical equation to determine the molar ratios of the reactants and products.
In a redox reaction, atoms change their oxidation states by losing or gaining electrons. The conservation of charge principle dictates that the number of electrons lost must equal the number of electrons gained. Applying this principle in stoichiometry involves using the balanced chemical equation to determine the molar ratios of the reactants and products.