Metal carbonyls having formula \(M(\mathrm{CO})_{x}\), where \(x\) is the number of carbonyl units co-ordinated to metal \(M\) are formed by Fe, \(\mathrm{Cr}\) and Ni. If effective atomic number of each metal is 36, what are the formula of metal carbonyls?

Short Answer

Expert verified
The metal carbonyl formulas are Fe(CO)_5, Cr(CO)_6, and Ni(CO)_4.

Step by step solution

01

Determine the atomic numbers of Fe, Cr, and Ni

Find the atomic numbers of Iron (Fe), Chromium (Cr), and Nickel (Ni) from the periodic table. The atomic numbers are as follows: Fe has 26, Cr has 24, and Ni has 28.
02

Calculate the number of electrons needed for an effective atomic number of 36

Since the effective atomic number (EAN) is 36 for each metal, calculate the number of electrons needed to reach the EAN for each metal. Substract the atomic number from the EAN to find the number of additional electrons required: EAN - atomic number = number of additional electrons needed.
03

Find the number of CO units required

Each CO molecule donates two electrons when coordinating with a metal. Divide the number of additional electrons needed by 2 to find the number of CO units required: number of additional electrons needed / 2 = number of CO units.
04

Write the metal carbonyl formulas

Use the number of CO units calculated in Step 3 to write the metal carbonyl formulas as M(CO)_x, where M is the metal and x is the number of CO units.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Effective Atomic Number
Effective atomic number (EAN) is a key concept in coordination chemistry, especially for metal carbonyls. It equates to the total number of protons that an atom's nucleus would have if the metal's electron cloud were to mimic the nearest noble gas configuration. In other words, it's the sum of the atom's actual protons plus the number of electrons donated by attached ligands like carbonyl (CO) groups.

When ligands bind to a metal, they can donate electron pairs, increasing the metal's total electron count. Researchers have observed that stable configurations often occur when metals in complexes have an EAN equivalent to the next noble gas. For example, iron (Fe), which has an atomic number of 26, often forms stable complexes when its EAN is 36, identical to the noble gas krypton. In the case of the metal carbonyls, each CO group contributes two electrons, which aids in achieving the desired EAN.
Coordination Chemistry
Coordination chemistry involves the study of compounds in which a central metal atom or ion is surrounded by non-metal ions or molecules, known as ligands. Metal carbonyls fall under this category, with carbon monoxide acting as a ligand. These compounds are characterized by the nature of the bond between the metal and the carbonyl group, where the metal atom provides vacant orbitals for bonding and the ligands offer electron pairs.

Coordination chemistry is not just about the formation of complexes, but also about understanding the properties and reactivities of these compounds. The structure, bond angles, and overall geometry around the central metal will affect the physical and chemical behavior of the complex. Transition metals are especially prolific in forming such complexes due to their d orbitals, which can accept electron pairs from ligands like CO, NH₃, or H₂O.
Periodic Table
The periodic table is a chemist's roadmap, organizing chemical elements by their atomic numbers, electron configurations, and recurring properties. To solve problems involving metal carbonyls, one must be adept at reading and extracting information from the periodic table, such as atomic numbers and group configurations.

A clear grasp of the periodic table allows students to understand that the transition metals like Fe, Cr, and Ni – which frequently form metal carbonyls – reside in the d-block of the table. This central location is key, as these elements have unfilled d orbitals that are instrumental in forming complexes with ligands. Furthermore, knowing the atomic numbers and positions of elements on the periodic table helps in predicting and explaining trends in their chemical behavior.
Electron Counting
Electron counting is a fundamental technique in coordination chemistry that involves tallying electrons to predict stability and reactivity in metal complexes. It can be split into two approaches: the neutral method and the oxidation state method. The neutral method treats all species as neutral, while the oxidation state method takes into consideration the charges.

For metal carbonyls, electron counting helps in determining the number of ligands that can attach to the metal center to satisfy its EAN. In studying the complexes mentioned in the exercise, we use electron counting to ensure that the metal achieves an electronic configuration resembling that of a noble gas. Given the rule that each CO ligand donates two electrons, this method simplifies calculating the number of CO ligands needed to achieve a certain EAN.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

\(1 \mathrm{~g}\) of \(\mathrm{Mg}\) atoms in the vapour phase absorbs \(50.0 \mathrm{~kJ}\) of energy. Find the composition of \(\mathrm{Mg}^{+}\) and \(\mathrm{Mg}^{2+}\) formed as a result of absorption of energy. \(\mathrm{IE}_{1}\) and \(\mathrm{IE}_{2}\) for \(\mathrm{Mg}\) are 740 and \(1450 \mathrm{~kJ} \mathrm{~mol}^{-1}\) respectively.

\(100 \mathrm{~mL}\) of \(1 \times 10^{-2} M\) aqueous solution of an organic compound were shaken with \(50 \mathrm{~mL}\) of an organic solvent till equilibrium is attained. Calculate the concentration of organic compound in organic solvent. Given that distribution coefficient of organic compound for the given solvent is 50 in favour of organic solvent.

Calculate the \(\%\) ionic character in \(\mathrm{HCl}\) molecule. Given bond length of \(\mathrm{HCl}\) is \(1.275 \AA\) and \(\mu_{\mathrm{HCi}}=1.03\) debye.

Assuming covalent radii to be additive property; calculate the iodine-iodine distances in \(o-, m-, p\) -di-iodobenzene. The benzene ring is regular hexagon and each \(C-\) I bond lies on a line passing through the centre of hexagon. The \(\mathrm{C}-\mathrm{C}\) bond length in \(\mathrm{C}_{6} \mathrm{H}_{6}\) are \(1.40 \AA\) and covalent radius of iodine and carbon atom are \(1.33 \AA\) and \(0.77 \AA\). Also neglect different overlapping effect.

A mixture contains atoms of fluorine and chlorine. The removal of an electron from each atom of sample absorbs \(284 \mathrm{~kJ}\) while the addition of an electron to each atom of mixture releases \(68.8 \mathrm{~kJ}\). Determine the percentage composition of mixture. Given \(\mathrm{IE}_{1}\) for \(\mathrm{F}\) and \(\mathrm{Cl}\) are \(27.91 \times 10^{-22}\) and \(20.77 \times 10^{-22} \mathrm{~kJ} /\) atom respectively and \(\mathrm{EA}_{1}\) for \(\mathrm{F}\) and \(\mathrm{Cl}\) are \(-5.53 \times 10^{-22}\) and \(-5.78 \times 10^{-22} \mathrm{~kJ} /\) atom respectively.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free