(a) When \(4.2 \mathrm{~g} \mathrm{NaHCO}_{3}\) is added to a solution \(\mathrm{of} \mathrm{CH}_{3} \mathrm{COOH}\) weighing \(10.0 \mathrm{~g}\), it is observed that \(2.2 \mathrm{~g} \mathrm{CO}_{2}\) is released into atmosphere. The residue is found to weigh \(12.0 \mathrm{~g}\). Show that these observations are in agreement with the low of conservation of weigh. (b) If \(6.3 \mathrm{~g}\) of \(\mathrm{NaHCO}_{3}\) are added to \(15.0 \mathrm{~g} \mathrm{CH}_{3} \mathrm{COOH}\) solution. The residue is found to weigh \(18.0 \mathrm{~g}\). What is the mass of \(\mathrm{CO}_{2}\) released in this reaction.

Short Answer

Expert verified
For part (a), the observations agree with the law of conservation of mass (total mass before and after the reaction is 14.2 g). For part (b), the mass of CO2 released is 3.3 g.

Step by step solution

01

Define the Principle of Conservation of Mass

Understand that the principle of conservation of mass states that in a chemical reaction, the total mass of the reactants equals the total mass of the products.
02

Calculate Total Initial Mass for Part (a)

Add the mass of NaHCO3 and the mass of CH3COOH to find the total initial mass before the reaction: 4.2 g NaHCO3 + 10.0 g CH3COOH = 14.2 g.
03

Calculate Total Final Mass for Part (a)

Add the mass of CO2 released and the residue to find the total final mass after the reaction: 2.2 g CO2 + 12.0 g residue = 14.2 g.
04

Compare Initial and Final Mass for Part (a)

Compare the total initial mass and total final mass to check if they agree according to the principle of conservation of mass.
05

Calculate Total Initial Mass for Part (b)

Calculate the total initial mass by adding the mass of NaHCO3 and the mass of CH3COOH: 6.3 g NaHCO3 + 15.0 g CH3COOH = 21.3 g.
06

Analyze the Total Final Mass for Part (b)

Observe that the final residue weighs 18.0 g after the reaction.
07

Calculate the Mass of CO2 Released in Part (b)

To find the mass of CO2 released, subtract the residue's mass from the total initial mass: 21.3 g (initial mass) - 18.0 g (residue) = 3.3 g CO2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reactions
At the heart of chemistry lies the concept of chemical reactions, where substances, known as reactants, transform into new substances referred to as products. These reactions are guided by the rearrangement of atoms, involving breaking and forming bonds, and are depicted symbolically through balanced chemical equations.

A common example involves the reaction between sodium bicarbonate ((NaHCO_3)) and acetic acid ((CH_3COOH)) to produce carbon dioxide ((CO_2)), water, and sodium acetate. In educational scenarios, like IIT-JEE physical chemistry, understanding the profound implications of these interactions, along with their underlying principles such as conservation of mass, provides a fundamental basis for mastering the subject.

Students must learn to not only to write balanced chemical equations but to also interpret the physical changes they represent, such as gases being released into the atmosphere, which is apparent in the problem provided.
Stoichiometry
Stoichiometry is the quantitative aspect of chemistry that relates to the measurement and calculation of the products and reactants in a chemical reaction. It uses the concept of the mole and balanced equations to ensure the law of conservation of mass is observed. A balanced equation has equal numbers of each type of atom on both sides of the reaction.

In practice, stoichiometry involves calculations based on the molar ratios in a balanced chemical equation. For instance, if the initial and final mass in a chemical reaction involving (NaHCO_3) and (CH_3COOH) are measured, stoichiometry could be applied to predict the mass of (CO_2) released.

Understanding stoichiometry is critical for correctly interpreting the results of the textbook exercise. If one knows the molar mass of reactants and products, stoichiometry allows the prediction of masses involved before and after the reaction, verifying the conservation of mass.
IIT-JEE Physical Chemistry
IIT-JEE is one of the most challenging engineering entrance exams in India, and physical chemistry is a significant component of the chemistry syllabus. This branch of chemistry concerns itself with understanding the physical properties of molecules, the forces that act upon them, and their behavior in chemical reactions.

Within the IIT-JEE context, mastering the stoichiometry and the conservation of mass in chemical reactions is crucial. These principles not only form the core questions in the Physical Chemistry section but also are the foundational concepts that help students tackle more complex problems. The exercises involving the mass of (NaHCO_3) reacting with (CH_3COOH) and the resulting (CO_2) release illustrate the kind of practical, conceptual questions a student might encounter.

An in-depth comprehension of these concepts supports students in applying them to assorted scenarios, which is essential for excelling in the IIT-JEE physical chemistry examinations.

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