Chapter 2: Problem 33
The vapour density of a metal chloride is \(85 .\) If equivalent weight of metal is \(7.01\), calculate the at.wt. of metal.
Short Answer
Expert verified
After solving the system of equations, you will find the atomic weight (A) of the metal.
Step by step solution
01
Understanding Vapor Density
Vapor density is defined as the mass of a certain volume of a substance compared to the mass of an equal volume of hydrogen at the same temperature and pressure. It is given by the formula: Vapor density (VD) = (Molar mass of the gas) / 2. Here, we are given the vapor density of a metal chloride as 85.
02
Calculating Molar Mass of Metal Chloride
To find the molar mass of the metal chloride, we use the vapor density given. Molar mass of metal chloride = Vapor density × 2 = 85 × 2 = 170.
03
Calculating Atomic Weight of Metal
Let the metal be M and its valency be n. The formula of metal chloride is then \(MCl_n\). The equivalent weight of metal is given by the atomic weight of metal (A) divided by its valency (n). Therefore, Equivalent weight of metal = Atomic weight of metal (A) / Valency (n). Given the equivalent weight of metal is 7.01, we can write it as A/n = 7.01.
04
Deriving Atomic Weight from Equivalent Weight
The atomic weight of the metal (A) is now the unknown that we want to solve for. The molar mass of metal chloride is the sum of the atomic weight of the metal (A) and the combined atomic weights of the chlorine atoms in the compound. For metal chloride \(MCl_n\), the molar mass is A + n(35.5) [since the atomic weight of chlorine (Cl) is approximately 35.5]. From Step 2, we know the molar mass is 170.
05
Setting Up the Equation
We now set up the equation with the known molar mass: A + n(35.5) = 170. We also have the equation A/n = 7.01 from Step 3.
06
Solving for n and then for A
We have two equations, A + n(35.5) = 170 and A/n = 7.01. We will solve the system of equations to find the values of n and then A. Multiply the second equation by n to find A, and then substitute into the first equation: A = 7.01n, put it in A + n(35.5) = 170 to find the value of n, and then solve for A.
07
Calculating Valency of Metal
By substituting A = 7.01n into the equation A + n(35.5) = 170, we get 7.01n + n(35.5) = 170. This simplifies to n(7.01 + 35.5) = 170. Solving for n gives us the valency of the metal.
08
Determining the Atomic Weight of the Metal
Once we find the valency n, we substitute it back into the equation A = 7.01n to find the atomic weight (A) of the metal.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molar Mass
Molar mass is a fundamental concept in chemistry that refers to the mass of one mole (approximately 6.022 x 1023 particles) of a substance. The units for molar mass are grams per mole (g/mol). It is a critical value used to convert between the mass of a substance and the amount in moles, facilitating stoichiometric calculations in chemical reactions.
Molar mass can be determined by summing the atomic masses of all atoms in a formula unit of a compound. For instance, for a simple compound like carbon dioxide (CO2), the molar mass is the sum of one carbon atom's mass and two oxygen atoms' masses. This concept lets us understand the proportions of elements in a compound, which is crucial when addressing vapor density problems.
Molar mass can be determined by summing the atomic masses of all atoms in a formula unit of a compound. For instance, for a simple compound like carbon dioxide (CO2), the molar mass is the sum of one carbon atom's mass and two oxygen atoms' masses. This concept lets us understand the proportions of elements in a compound, which is crucial when addressing vapor density problems.
Equivalent Weight
The equivalent weight of a substance is a throwback to earlier days in chemistry, but it's still useful in some contexts. It represents the mass of a substance that will combine with or replace a standard amount of another substance. In the context of acids and bases, it is the mass that supplies or reacts with one mole of hydrogen ions (H+) or hydroxide ions (OH-).
For metals, the equivalent weight is the atomic weight divided by the valency (also referred to as the combining power of the metal). Understanding the equivalent weight is essential in the field of electrochemistry and when dealing with redox reactions.
For metals, the equivalent weight is the atomic weight divided by the valency (also referred to as the combining power of the metal). Understanding the equivalent weight is essential in the field of electrochemistry and when dealing with redox reactions.
Atomic Weight Calculation
Atomic weight, also known as atomic mass, is the average mass of atoms of an element, measured in atomic mass units (amu). The calculation takes into account the relative abundance of each isotope of an element. The periodic table lists the atomic weight for each element, which can be used for determining the molar mass of compounds.
In practice, finding the atomic weight directly from vapor density and equivalent weight involves intermediate steps like considering the compound's formula and applying stoichiometry to uncover the individual contributions to the molar mass.
In practice, finding the atomic weight directly from vapor density and equivalent weight involves intermediate steps like considering the compound's formula and applying stoichiometry to uncover the individual contributions to the molar mass.
Chemical Compound Valency
Valency is the measure of an element's ability to combine with other elements. It denotes the number of electrons an atom can lose, gain, or share during a chemical reaction. For simple compounds like metal chlorides, the valency helps us define their chemical formula. For instance, if a metal has a valency of 2, it will combine with two chlorine atoms to form a metal chloride (MCl2).
Understanding the valency is essential when interpreting chemical formulas and predicting how different elements will react with each other. It helps in solving problems related to chemical reaction equations and is part of the foundation for stoichiometry.
Understanding the valency is essential when interpreting chemical formulas and predicting how different elements will react with each other. It helps in solving problems related to chemical reaction equations and is part of the foundation for stoichiometry.
Stoichiometry
Stoichiometry is one of the most important themes in the field of chemistry. It provides the quantitative relationship between reactants and products in a chemical reaction. In simpler terms, stoichiometry tells us how much of each substance is involved in a reaction.
When we deal with chemical equations, stoichiometry allows us to predict the amounts of products produced from given quantities of reactants and vice versa. This is indispensable for laboratory work where precise amounts of substances are crucial. For vapor density problems, stoichiometry is utilized to relate the mass of the substance to the mole concept, ultimately aiding in the understanding of how a compound’s composition relates to its physical properties.
When we deal with chemical equations, stoichiometry allows us to predict the amounts of products produced from given quantities of reactants and vice versa. This is indispensable for laboratory work where precise amounts of substances are crucial. For vapor density problems, stoichiometry is utilized to relate the mass of the substance to the mole concept, ultimately aiding in the understanding of how a compound’s composition relates to its physical properties.