\(5.325 \mathrm{~g}\) sample of methyl benzoate, a compound used in the manufacture of perfumes is found to contain \(3.758 \mathrm{~g}\) of carbon, \(0.316\) \(\mathrm{g}\) hydrogen and \(1.251 \mathrm{~g}\) of oxygen. What is empirical formulia of compound. If mol. weight of methyl benzoate is \(136.0\), calculate its molecular formula.

Short Answer

Expert verified
The empirical formula of methyl benzoate is C3H3O. The molecular formula is C8H8O2.

Step by step solution

01

Determine Moles of Atoms

Calculate the moles of carbon (C), hydrogen (H), and oxygen (O) by dividing the mass of each element by its atomic mass (12.01 for C, 1.008 for H, and 16.00 for O). For carbon: moles of C = mass of C / atomic mass of C. For hydrogen: moles of H = mass of H / atomic mass of H. For oxygen: moles of O = mass of O / atomic mass of O.
02

Calculate the Empirical Formula

To find the simplest whole number ratio, divide the moles of each element by the smallest number of moles calculated in step 1. If necessary, multiply the resulting ratios by whole numbers to get whole number subscripts for the empirical formula.
03

Determine the Molecular Formula

Divide the molar mass of methyl benzoate (136.0 g/mol) by the molar mass of the empirical formula to get a ratio. Multiply the empirical formula by this ratio to get the molecular formula.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is the study of the quantitative relationships, or ratios, between reactants and products in chemical reactions. It encompasses a series of calculations that allow chemists to predict the amounts of substances consumed and produced in a given reaction. These relationships are determined by the laws of conservation of mass and fixed proportions, which state that in any chemical reaction, mass is neither created nor destroyed, and elements combine in fixed, whole-number ratios.

When solving stoichiometric problems, it’s crucial to use a balanced chemical equation, which provides the mole ratio of reactants and products. This ratio serves as a conversion factor to relate different entities in a reaction, such as grams, liters, particles, or moles. In the context of empirical and molecular formula calculations, stoichiometry helps in determining the amount of each element in a compound, allowing for the calculation of the compound's simplest formula (empirical formula) and its actual formula (molecular formula).
Mole Concept
The mole concept is a fundamental principle in chemistry that defines the mole as a unit of measurement for amount of substance. One mole corresponds to Avogadro's number (\(6.022 \times 10^{23}\) entities) of atoms, molecules, ions, or other particles.

The mole concept provides a bridge between the atomic level and the macroscopic world, since it allows chemists to count particles by weighing them. When calculating the empirical formula, the first step requires converting the mass of each element to moles using the element's atomic mass as a conversion factor. This conversion permits comparison of amounts on a per-atom basis, ensuring that the ratios calculated truly reflect the proportions of atoms in the compound. By understanding this concept, students can accurately determine the proportions of different elements in a chemical substance.
Atomic Mass
Atomic mass, often referred to as atomic weight, is the weighted average mass of an atom of an element based on the relative abundance of that element's isotopes. It is measured in atomic mass units (amu), where one amu is defined as one-twelfth the mass of a carbon-12 atom.

When calculating empirical formulas, the atomic mass acts as a crucial conversion factor between mass in grams and amount in moles. For example, in the provided exercise, the masses of carbon (C), hydrogen (H), and oxygen (O) are divided by their respective atomic masses, providing the amount of moles of each element present in the sample. This step is fundamental for determining the ratios of atoms in the compound, and it relies on accurate values for the atomic mass of each element.
Molar Mass
Molar mass is the mass of one mole of a substance (element or compound) and is expressed in units of grams per mole (g/mol). Calculating the molar mass involves summing the atomic masses of all the atoms in a molecule. It is an essential concept when relating the mass of a substance to the amount in moles, bridging the gap between mass on a laboratory scale and the number of particles on the atomic scale.

In the textbook exercise, after determining the empirical formula, the next step is to compare the molar mass of the empirical formula with the given molar mass of the compound (136.0 g/mol). This comparison reveals how many empirical formula units make up the molecular formula of methyl benzoate. By ensuring a comprehensive understanding of molar mass, students can seamlessly move from the empirical to the molecular formula of a compound.

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