A solution of glucose in water is labelled as 10 per cent \(w / w\), what would be the molality and mole fraction of each component in the solution? If the density of the solution is \(1.2 \mathrm{~g} \mathrm{~mL}^{-1}\), then what shall be the molarity of the solution?

Short Answer

Expert verified
Molality: 0.618 mol/kg, Mole fraction of glucose: 0.011, Mole fraction of water: 0.989, Molarity: 0.667 M.

Step by step solution

01

Understand Percent by Mass

The given 10% concentration of the glucose solution is by mass, which means 10 grams of glucose is present in 100 grams of the solution.
02

Calculate the Mass of Water

The mass of the solution is 100 grams, so the mass of water in the solution can be calculated by subtracting the mass of glucose from the total mass. Mass of water = 100 grams (total mass) - 10 grams (mass of glucose) = 90 grams.
03

Calculate Molality

Molality is defined as the moles of solute per kilogram of solvent. Calculate the moles of glucose ({C_6H_{12}O_6}) using its molar mass (approximately 180 g/mol). Moles of glucose = 10 grams / 180 g/mol = 0.0556 moles. Now, convert the mass of water to kilograms: 90 grams = 0.09 kg. Finally, calculate molality: Molality = 0.0556 moles / 0.09 kg = 0.618 mol/kg.
04

Calculate Mole Fraction of Each Component

First, calculate the mole fraction of glucose. Mole fraction of glucose = moles of glucose / (moles of glucose + moles of water). Moles of water can be calculated using its molar mass (18 g/mol): Moles of water = 90 grams / 18 g/mol = 5 moles. Thus, Mole fraction of glucose = 0.0556 / (0.0556 + 5) = 0.011. Next, to find the mole fraction of water, subtract the mole fraction of glucose from 1: Mole fraction of water = 1 - Mole fraction of glucose = 1 - 0.011 = 0.989.
05

Calculate Molarity

The molarity can be calculated by finding the moles of solute per liter of solution. First, find the volume of the solution using density. With the density ({1.2 g/mL}) and total mass of the solution (100 g), Volume = mass / density = 100 g / 1.2 g/mL = 83.33 mL or 0.08333 L. Using the moles of glucose calculated earlier (0.0556 moles), the molarity is then: Molarity = moles of solute / volume of solution in liters = 0.0556 moles / 0.08333 L = 0.667 M.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Percent by Mass
When we talk about 'percent by mass' in a chemical solution, we're discussing how much of the solution's weight is made up by a particular component. In educational terms, think of it like how much of a backpack's weight is due to textbooks. If a solution is 10% glucose by mass, it's like saying out of every 100 grams of our backpack's weight, 10 grams are due to textbooks. Mathematically, if you have a 10% w/w (weight/weight) glucose solution, you can calculate the mass of glucose and the mass of the solvent (usually water) separately, as is the case in our exercise. It is crucial for students to grasp this concept because it lays the foundation for calculating other parameters like molality and molarity which help in understanding the solution's concentration.
Molarity Calculation
Molarity is an important concept when discussing solution concentrations in chemistry. It tells us the number of moles of a solute present in one liter of solution. Think of it like measuring how many apples you have in one basket -- it's a way to quantify the 'amount' of solute in a given volume of solution, with the 'basket' being a liter of solution here.

To perform a molarity calculation, as seen in the exercise, you'd divide the number of moles of your solute by the total volume of your solution in liters. One common stumbling block for students is converting milliliters to liters correctly. Always remember that 1000 milliliters make up one liter. This step is especially important because molarity is expressed in terms of liters, not milliliters, and getting the conversion wrong can lead to incorrect molarity values.
Chemical Solution Concentration
The concentration of a chemical solution is a measure of how much solute is dissolved in a certain amount of solvent. There are various ways to express this concentration, such as percent by mass, molality, and molarity, each serving a different purpose depending on the scenario.

Percent by mass is typically used when the solution's physical properties, like density, are relevant. Molality is preferred in situations involving changes in temperature, as it doesn't change with varying temperatures because it's based on mass, not volume. Molarity, on the other hand, is used when working with reaction rates and volumes in chemical reactions, as it relates to the volume of the solution. In an educational setting, ensuring students understand these nuanced differences is fundamental to correctly applying the concepts in laboratory and real-world scenarios.

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