Identify the substance acting as oxidunt or reductant if any in the following: (i) \(\mathrm{AICl}_{3}+3 \mathrm{~K} \longrightarrow \mathrm{Al}+3 \mathrm{KCI}\) (ii) \(\mathrm{SO}_{2}+2 \mathrm{H}_{2} \mathrm{~S} \longrightarrow 3 \mathrm{~S}+\mathrm{H}_{2} \mathrm{O}\) (iii) \(\mathrm{BaCl}_{2}+\mathrm{Na}_{2} \mathrm{SO}_{4} \longrightarrow \mathrm{BaSO}_{4}+2 \mathrm{NaCl}\) (iv) \(3 \mathrm{I}_{2}+6 \mathrm{NaOH} \longrightarrow \mathrm{NalO}_{3}+5 \mathrm{NaI}+3 \mathrm{H}_{2} \mathrm{O}\)

Short Answer

Expert verified
\(\mathrm{AlCl}_{3}\) and \(\mathrm{SO}_{2}\) act as oxidants; elemental K and \(\mathrm{H}_{2}S\) act as reductants for reactions (i) and (ii), respectively. There is no oxidant or reductant in reaction (iii). For reaction (iv), \(\mathrm{I}_{2}\) acts as both an oxidant and reductant.

Step by step solution

01

Analyze the oxidation states of atoms in the first reaction

Examine the change in oxidation states of the elements in the reaction \(\mathrm{AlCl}_{3}+3\mathrm{K} \longrightarrow \mathrm{Al}+3\mathrm{KCl}\). Aluminium (Al) goes from an oxidation state of +3 in \(\mathrm{AlCl}_{3}\) to 0 in elemental Al. Potassium (K) goes from 0 in elemental K to +1 in \(\mathrm{KCl}\).
02

Identify the oxidant and reductant in the first reaction

Since Al is reduced (decrease in oxidation state), \(\mathrm{AlCl}_{3}\) is the oxidant. Because K is oxidized (increase in oxidation state), elemental K is the reductant.
03

Analyze the oxidation states of atoms in the second reaction

Review the change in oxidation states of the elements in the reaction \(\mathrm{SO}_{2}+2\mathrm{H}_{2}S \longrightarrow 3\mathrm{S}+\mathrm{H}_{2}O\). Sulfur in \(\mathrm{SO}_{2}\) goes from +4 to 0 in elemental S. Sulfur in \(\mathrm{H}_{2}S\) goes from -2 to 0.
04

Identify the oxidant and reductant in the second reaction

Since the sulfur in \(\mathrm{SO}_{2}\) is reduced, \(\mathrm{SO}_{2}\) is the oxidant. The sulfur in \(\mathrm{H}_{2}S\) is oxidized, making \(\mathrm{H}_{2}S\) the reductant.
05

Analyze the oxidation states of atoms in the third reaction

Analyze the change in oxidation states of the elements in the reaction \(\mathrm{BaCl}_{2}+\mathrm{Na}_{2}\mathrm{SO}_{4} \longrightarrow \mathrm{BaSO}_{4}+2\mathrm{NaCl}\). No change in oxidation states occurs because all elements maintain their oxidation states before and after the reaction.
06

Determine if there is an oxidant or reductant in the third reaction

Since no elements change their oxidation state, there is neither an oxidant nor a reductant in this reaction.
07

Analyze the oxidation states of atoms in the fourth reaction

Inspect the change in oxidation states of the elements in the reaction \(3\mathrm{I}_{2}+6\mathrm{NaOH} \longrightarrow \mathrm{NaIO}_{3}+5\mathrm{NaI}+3\mathrm{H}_{2}O\). Iodine (I) in \(\mathrm{I}_{2}\) goes from 0 to +5 in \(\mathrm{NaIO}_{3}\) and to -1 in \(\mathrm{NaI}\).
08

Identify the oxidant and reductant in the fourth reaction

Since iodine goes from 0 to +5, \(\mathrm{I}_{2}\) is the oxidant for the formation of \(\mathrm{NaIO}_{3}\). Simultaneously, a different iodine atom goes from 0 to -1; hence, \(\mathrm{I}_{2}\) also acts as a reductant for the formation of \(\mathrm{NaI}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation States
Understanding oxidation states is essential for analyzing and predicting the outcome of oxidation-reduction (redox) reactions. An oxidation state, often referred to as an oxidation number, is a theoretical charge on an atom if the compound was composed of ions. This number helps determine how electrons are distributed in a chemical reaction.

For instance, in the reaction \(\mathrm{AlCl}_{3}+3\mathrm{~K} \longrightarrow \mathrm{Al}+3\mathrm{KCl}\), aluminum changes its oxidation state from +3 to 0, indicating a gain of electrons or reduction. Similarly, potassium changes its oxidation state from 0 to +1, representing a loss of electrons, or oxidation. Analyzing the shift in these numbers allows us to identify the electron flow and understand the roles substances play in the reaction.

In this context, improvements can be made by practicing the determination of oxidation states for various elements in compounds and understanding the general rules, such as oxygen being -2 in most compounds and the sum of oxidation states in a neutral compound being zero. With practice, one can swiftly identify changes in these states within reaction equations, a necessary skill for dissecting redox reactions.
Oxidants and Reductants
In a redox reaction, substances that accept electrons are called oxidants (or oxidizing agents), while those that donate electrons are known as reductants (or reducing agents). An oxidant gets reduced in the process, whereas a reductant is oxidized.

From our example reactions, \(\mathrm{AlCl}_{3}\) and \(\mathrm{SO}_{2}\) serve as oxidants because they gain electrons and undergo reduction. On the other hand, elemental potassium (K) and \(\mathrm{H}_{2}S\) act as reductants because they lose electrons.

Identifying Oxidants and Reductants

Notice that substances which have their oxidation state decreased in a reaction are the oxidants, and the ones that have their oxidation state increased are the reductants. This concept is pivotal to understanding how electrons are transferred between reactants, allowing chemists to predict the direction and products of a redox reaction.
Chemical Reaction Analysis
Chemical reaction analysis involves studying the reactants and products to determine the nature of the chemical change. A key part of this analysis is identifying whether a reaction is a redox process, which includes the transfer of electrons between substances.

In the given reactions, analyzing the change in oxidation states helps us to ascertain whether each reaction is redox or not. For example, \(\mathrm{BaCl}_{2}+\mathrm{Na}_{2}\mathrm{SO}_{4} \longrightarrow \mathrm{BaSO}_{4}+2\mathrm{NaCl}\) shows no change in the oxidation states of the involved elements, indicating it is not a redox reaction. In contrast, the reaction between iodine and sodium hydroxide shows iodine in \(\mathrm{I}_{2}\) doing double duty as both an oxidant and a reductant, which we identify by observing changes in its oxidation state.

To improve analysis skills, focusing on the systematic determination of the oxidation states and changes occurring during the reaction can lead to a clear understanding of the overall chemical process. Through practice, distinguishing between redox and non-redox reactions becomes more intuitive, allowing for a quick assessment of the role each substance plays in a chemical equation.

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Most popular questions from this chapter

Write the half reactions for the following redox reactions: (a) \(2 \mathrm{Fe}^{3+}{ }_{\text {(aq. })}+2 \mathrm{I}_{(\mathrm{aq})} \longrightarrow 2 \mathrm{Fe}^{2+}{ }_{\text {(aq.) }}+\mathrm{I}_{2(\mathrm{aq} .)}\) (b) \(\mathrm{Zn}_{(\mathrm{s})}+2 \mathrm{H}_{(\text {aq. })}^{+} \longrightarrow \mathrm{Zn}^{2+}\) (aq.) \(+\mathrm{H}_{2(\mathrm{~g})}\) (c) \(\mathrm{Al}_{(\mathrm{s})}+3 \mathrm{Ag}^{+}{ }_{\text {(aq.) }} \longrightarrow \mathrm{Al}_{\text {(aq.) }}^{3+}+3 \mathrm{Ag}_{(\mathrm{s})}\)

Select the nature or type of redox change in the following reactions: (ii) \(2 \mathrm{Cu}^{+} \longrightarrow \mathrm{Cu}^{2+}+\mathrm{Cu}^{0}\) (b) \(\quad \mathrm{Cl}_{2} \longrightarrow \mathrm{ClO}^{-}+\mathrm{Cl}^{-}\) (c) \(2 \mathrm{KClO}_{3} \stackrel{\Delta}{\longrightarrow} 2 \mathrm{KCl}+3 \mathrm{O}_{2}\) (d) \(\quad\left(\mathrm{NH}_{4}\right)_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \longrightarrow \mathrm{N}_{2}+\mathrm{Cr}_{2} \mathrm{O}_{3}+4 \mathrm{H}_{2} \mathrm{O}\) (e) \(10 \mathrm{FeSO}_{4}+2 \mathrm{KMnO}_{4}+8 \mathrm{H}_{2} \mathrm{SO}_{4} \longrightarrow 2 \mathrm{MnSO}_{4}+5 \mathrm{Fe}_{2}\left(\mathrm{SO}_{4}\right)_{3}+\) \(\mathrm{K}_{2} \mathrm{SO}_{4}+8 \mathrm{H}_{2} \mathrm{O}\) (f) \(5 \mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}+2 \mathrm{KMnO}_{4}+3 \mathrm{H}_{2} \mathrm{SO}_{4} \longrightarrow \mathrm{K}_{2} \mathrm{SO}_{4}+2 \mathrm{MnSO}_{4}+\) \(10 \mathrm{CO}_{2}+8 \mathrm{H}_{2} \mathrm{O}\)

$$ \begin{aligned} &\text { Point out the oxidation number of } \mathrm{C} \text { in the following : }\\\ &\mathrm{CH}_{4}, \mathrm{C}_{3} \mathrm{H}_{8}, \mathrm{C}_{2} \mathrm{H}_{6}, \mathrm{C}_{4} \mathrm{H}_{10}, \mathrm{CO}, \mathrm{CO}_{2} \text { and } \mathrm{HCO}_{3}^{-}, \mathrm{CO}_{3}^{2-} \end{aligned} $$

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